Time period of a conical pendulum by D'Alembert's principle

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SUMMARY

The time period of a conical pendulum can be derived using D'Alembert's principle, resulting in the formula T = 2π√(r/(g tan θ)). The discussion emphasizes the importance of considering virtual displacements in both the radial and angular directions, particularly in spherical coordinates. It highlights that while the angle θ remains constant for the specific solution, virtual displacements can still be applied without violating the system's constraints. The key to solving the problem lies in correctly applying D'Alembert's principle with the appropriate coordinate system.

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  • D'Alembert's principle in classical mechanics
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justwild
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Homework Statement


Finding the time period of a conical pendulum by D'Alembert's principle. The string is of a constant length and all dissipations are to be ignored.

Homework Equations


The time period of a conical pendulum is 2\pi \sqrt{\frac{r}{g\tan\theta}}. I need to arrive at this result starting from the D'Alembert's principle.

The Attempt at a Solution


I assume a cylindrical coordinates system whose origin coincides with the fulcrum of the pendulum. Thus, for the conical pendulum with constant string length, the acceleration of the particle would be
\ddot{\vec{r}}=\ddot{\rho}\hat{\rho}+\rho\ddot{\phi}\hat{\phi}.
Now the virtual displacement can be given as
\delta\vec{r}=\rho\delta\phi\hat{\phi}.
And the force acting on the particle as \vec{F}=-mg\hat{z}.

Now if I substitute all these in the D'Alembert's principle, I won't be able to calculate the time period from there. This is obvious because the virtual displacement does not contain the \hat{z} term and due to the dot product, the expression won't include any g term which is necessary because the result does contain the g term.
I am out of ideas for now and I would appreciate anyone from the PF helping me out.
 
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Hello, justwild.

What about virtual displacements in the ##\hat{\theta}## direction. For acceleration in spherical coordinates see here.
 
TSny said:
What about virtual displacements in the ##\hat{\theta}## direction.
I don't understand. Even if I assume a spherical coordinates system why would there be a component of acceleration in the ##\hat{\theta}## direction?
Isn't ##\theta## supposed to remain constant during the motion?
 
justwild said:
I don't understand. Even if I assume a spherical coordinates system why would there be a component of acceleration in the ##\hat{\theta}## direction?
Isn't ##\theta## supposed to remain constant during the motion?

Yes, for the particular solution that you are considering θ will remain constant. However, in http://en.wikipedia.org/wiki/D'Alembert's_principle]d'Alembert's[/PLAIN] principle you can consider any virtual displacement that doesn't violate the physical constraint of the system.
 
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Use Cartesian co-ordinates. Take the length of the string=constant to be the constraint eq. Find delta(z).
Substitute values in d'alemberts', put delta (z).
You'll be able to find the time period
 

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