Time taken for a planet to collide with the Sun

Click For Summary
SUMMARY

The discussion centers on calculating the time it would take for a planet to collide with the Sun if it were abruptly stopped in its circular orbit. The key formula referenced is T=2π (r^3/GM)^(1/2), which relates the orbital period to the radius and gravitational constant. Participants highlight two primary methods for solving the problem: one involving differential equations and the other utilizing Kepler's laws. The conversation emphasizes the complexity of the calculations and the importance of understanding the implications of changing the planet's velocity.

PREREQUISITES
  • Understanding of Kepler's laws of planetary motion
  • Familiarity with differential equations
  • Knowledge of gravitational force and its mathematical representation
  • Basic physics concepts related to orbits and motion
NEXT STEPS
  • Study the application of Kepler's laws in orbital mechanics
  • Learn how to solve differential equations in the context of gravitational systems
  • Explore the implications of changing orbital velocities on planetary motion
  • Review tutorials on drawing ellipses and understanding their properties
USEFUL FOR

Students in undergraduate or secondary school physics, educators teaching orbital mechanics, and anyone interested in celestial dynamics and gravitational interactions.

someone_2156
Messages
5
Reaction score
0
Thread moved from the technical forums to the schoolwork forums
TL;DR Summary: if a planet was suddenly stopped in its orbit, suppose to be circular, find how much time will it take in falling onto the sun(in terms of time period)

I know that T=2pi (r^3/GM)^1/2 and a=GM/x^2
how to proceed further
 
Last edited:
Physics news on Phys.org
Your approach won't work because the ##x=c_1+c_2t+\frac 12at^2## approach you are trying only works if ##a## is constant. You would need to solve the differential equation you started with. Deciding whether you are using ##x## or ##R## for the planet's position will help with that, but it produces a fairly nasty answer.

Are you familiar with Kepler's laws?
 
What would happen to the period of the orbit if you abruptly slowed, rather than stopped, the planet? And if you did it again but slowed it more? What is the limit of that if you stop the planet?
 
Also, you may want to read the LaTeX Guide linked immediately below the reply box if you are posting maths.
 
Ibix said:
What would happen to the period of the orbit if you abruptly slowed, rather than stopped, the planet? And if you did it again but slowed it more? What is the limit of that if you stop the planet?
i am not sure about this. i know that t^2 is directly proportionl to the cube of semi major axis
 
someone_2156 said:
i am not sure about this. i know that t^2 is directly proportionl to the cube of semi major axis
There are two ways to solve the problem. The first involves solving a differential equation - which is quite hard. The second is a neat trick using Kepler's laws. It's not easy, however, to figure out the trick if you haven't seen it before.

Where did you get this problem and what level of physics are you studying?
 
PeroK said:
There are two ways to solve the problem. The first involves solving a differential equation - which is quite hard. The second is a neat trick using Kepler's laws. It's not easy, however, to figure out the trick if you haven't seen it before.

Where did you get this problem and what level of physics are you studying?
undergraduate/ secondary school and I got this problem from a question bank. Can you explain the second method?
 
someone_2156 said:
undergraduate/ secondary school and I got this problem from a question bank. Can you explain the second method?
What happens if, instead of stopping the planet, you leave the planet with a small tangential velocity? Imagine the star and planet are point masses.
 
  • Like
  • Informative
Likes   Reactions: Juanda and SammyS
PeroK said:
What happens if, instead of stopping the planet, you leave the planet with a small tangential velocity? Imagine the star and planet are point masses.
the orbit would flatten more and the closest approach to the sun would be very near
 
  • #10
someone_2156 said:
the orbit would flatten more and the closest approach to the sun would be very near
Try to do some calculations using Kepler's laws.
 
  • #11
someone_2156 said:
the orbit would flatten more and the closest approach to the sun would be very near
The key thing to think about is where the foci of the ellipse move to. In the circular case, both foci are at the center. Where are they in the extremal case as the circle flattens more and more?

Hint: there's probably a tutorial on the web on how to draw an ellipse with string and a pair of pins.
 

Similar threads

  • · Replies 12 ·
Replies
12
Views
4K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 12 ·
Replies
12
Views
5K
  • · Replies 1 ·
Replies
1
Views
10K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K