Tire rolling down slope - angle - friction

[mybrohshi5]

Homework Statement

Suppose the hoop were a tire. A typical coefficient of static friction between tire rubber and dry pavement is 0.88. If the angle of the slope were variable,

what would be the steepest slope down which the hoop could roll without slipping?

The Attempt at a Solution

using the x components i came up with

mgsin($\theta$) - f_fric = m*a

since $\mu = \frac{f_{fric}}{N}$ then f_fric = $\mu$*(mgcos$\theta$)

so i put those together and came up with

mgsin$\theta$ - 0.88(mgcos$\theta$) = ma

mass cancels out so

gsin$\theta$ - 0.88(gcos$\theta$) = a

This is where i am stuck.

Any help would be great :) thank you

 

[cjpgconman]

You're on the right track and close!
You just have to find the force of friction
so from the sum of forces in the x direction and the torque equation, respectively, we have this:
mg sinθ - friction = m a friction * R = I a / R
Since the moment of inertia for a hoop is mr^2 and we replace that in the torque equation and solve for acceleration we get:
Torque:
friction*R=(mR^2)*(a/R)
Friction=m*a
so a=Friction/m

Now we substitute that in the sum of forces in the x direction
we get:
mg sinθ-friction = friction
friction = (m*g*sinθ)/2
now we just need a second equation for friction which is:
friction=Normal*mu
and the equation for normal is:
N=m*g*cosθ
solve for θ (to get it you'll have to take the inverse tangent)

Hope that helps it worked for me

 

[mybrohshi5]

Thank you :)

That worked perfectly