To calculate work done from a graph

[esha]

In the given question part (a) I don't understand why the work done is negative? The answer says that the displacement is along positive x direction (i understand that) while force acting on the particle is along negative x direction ( why is that? since it appears that as the value of x is increasing so is the value of force. )

 

[Doc Al]

while force acting on the particle is along negative x direction

The value of the force is negative in that region, thus it points opposite to the displacement.

 

[esha]

So it means that it doesn't matter doesn't matter whether the force is increasing or not in the negative region the force is increasing or not in the negative region

 

[Doc Al]

So it means that it doesn't matter doesn't matter whether the force is increasing or not in the negative region the force is increasing or not in the negative region

Right. As long as the force and displacement are in opposite directions, the work done by the force will be negative.

 

[esha]

oh... ok... its so fairly simple then