- #1

Jason DiCaprio

So I was curious about something. Having a flat tire today and having to change my tire made me wonder. I understand torque and force are 2 different things though related they have separate meanings.

So my question is if I have a 2 foot tire iron and I am torquing my nuts. Let's say they reached maximum torque and I can't move the tire iron anymore. Now let's say I am applying 10 pounds of force at 1 foot from the nut. My question is will I be adding 10 pounds of weight to the car/front wheel If I can't torque anymore and the nut is as tight as possible.

What if I was applying 10 pounds at 2 feet from the nut, common sense tells me I should be adding the same amount of weight to the car regardless if I apply the weight on the tire iron 1 foot away , 2 feet or any amount of feet. Weight should be weight. But I understand the torque will be increasing on the nut as I move farther and farther away from the nut.

My question is how is it possible to increase the torque on the nut but have the same amount of weight pushing down on the nut(net weight being added to the car). What if I had some ridiculously long tire iron and I was 10 feet away pushing down 10 pounds the added weight to the car should still be the car + tire iron + plus the downward force that I'm applying to the tire iron which is 10 pounds, but then I would have a ridiculous amount of torque on the bolt.

So how is this possible for the weight/force applied to the weight of the car always being car + tire iron + 10 pounds force I am applying at any location on the tire iron but the torque will change so drastically on the nut depending on where I apply the pressure. It makes no sense to me how you can have such a variation of torque , but when the bolt is as tight as possible the extra torque from the leverage all turns into the same weight/force pushing down no matter where it is on the lever?

So my question is if I have a 2 foot tire iron and I am torquing my nuts. Let's say they reached maximum torque and I can't move the tire iron anymore. Now let's say I am applying 10 pounds of force at 1 foot from the nut. My question is will I be adding 10 pounds of weight to the car/front wheel If I can't torque anymore and the nut is as tight as possible.

What if I was applying 10 pounds at 2 feet from the nut, common sense tells me I should be adding the same amount of weight to the car regardless if I apply the weight on the tire iron 1 foot away , 2 feet or any amount of feet. Weight should be weight. But I understand the torque will be increasing on the nut as I move farther and farther away from the nut.

My question is how is it possible to increase the torque on the nut but have the same amount of weight pushing down on the nut(net weight being added to the car). What if I had some ridiculously long tire iron and I was 10 feet away pushing down 10 pounds the added weight to the car should still be the car + tire iron + plus the downward force that I'm applying to the tire iron which is 10 pounds, but then I would have a ridiculous amount of torque on the bolt.

So how is this possible for the weight/force applied to the weight of the car always being car + tire iron + 10 pounds force I am applying at any location on the tire iron but the torque will change so drastically on the nut depending on where I apply the pressure. It makes no sense to me how you can have such a variation of torque , but when the bolt is as tight as possible the extra torque from the leverage all turns into the same weight/force pushing down no matter where it is on the lever?

Last edited by a moderator: