Torque Calculation for Sweeper machine Broom

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Discussion Overview

The discussion revolves around calculating the torque required for a rotating sweeper machine broom, focusing on both the initial torque needed to start rotation and the continuous operating torque during use. Participants explore various aspects of torque calculation, including angular momentum, moment of inertia, and the effects of friction and bristle size.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant inquires about the torque calculation for a sweeper machine broom with specific dimensions and weight.
  • Another participant discusses the need for unbalanced torque to initiate rotation and questions the change in angular momentum when starting from rest.
  • Several participants reference the equation for torque and express confusion regarding the moment of inertia and its calculation.
  • One participant suggests that the torque needed to maintain rotation depends on various factors, including the contact pattern with the surface and friction.
  • A participant provides a rough estimate of the torque needed based on weight and friction, calculating it to be approximately 44.1 Nm, but questions whether more torque is needed for continuous operation.
  • Another participant clarifies that the estimated torque may only represent the startup torque and that additional torque may be necessary for constant rotation under certain conditions.

Areas of Agreement / Disagreement

Participants express differing views on the factors affecting torque requirements, including the distinction between startup torque and continuous operating torque. There is no consensus on the exact calculations or the necessary torque values.

Contextual Notes

Some participants express uncertainty regarding the definitions and calculations of moment of inertia and angular momentum, and there are unresolved questions about the specific conditions affecting torque requirements.

Tejas Patel
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Can anybody tell me how to calculate torque for rotating sweeper machine broom?

Broom Dia is - 0.6 m
Length - 2 m
Weight - 150 Kg
Rotating RPM - 150
 
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To start rotating any object, there has to be an unbalanced torque. Let the torque required be ##\tau##.
What is the change in angular momentum when rod starts rotating with the required RPM starting from rest?
 
AdityaDev said:
To start rotating any object, there has to be an unbalanced torque. Let the torque required be ##\tau##.
What is the change in angular momentum when rod starts rotating with the required RPM starting from rest?

I don't know about angular momentum, But i know time. In 10 sec shaft pick its max speed 150 RPM.
 
Are you familiar with this equation: ##\tau=\Delta I\omega##

edit:##\tau = \Delta (I\omega)/\Delta t##
 
Last edited:
AdityaDev said:
Are you familiar with this equation: ##\tau=\Delta I\omega##

Yes in this i have calculated w, angular speed come is 15.7 rad/s. But i have confusion regarding I
 
Assuming its a rod rotating about one end, I=(1/3)ML^2
 
AdityaDev said:
Assuming its a rod rotating about one end, I=(1/3)ML^2

In this what is M and L?
 
I is the moment of inertia which is analogous to mass in rotational mechanics. M is the mass and L is length of rod.
 
AdityaDev said:
I is the moment of inertia which is analogous to mass in rotational mechanics. M is the mass and L is length of rod.

than I value is 2594.75 N-M2
 
  • #10
So you can find the torque using the equation in post 4
 
  • #11
AdityaDev said:
So you can find the torque using the equation in post 4
Than Unit come in N-m2/s ? bcz w unit is rad/s and I N-m2 so bit confuse in this
 
  • #12
Oops... I am very sorry.
its ##\tau=I\alpha=I\frac{d\omega}{dt}##
 
  • #13
AdityaDev said:
Oops... I am very sorry.
its ##\tau=I\alpha=I\frac{d\omega}{dt}##
Ok thank you so much.
 
  • #14
What I am trying to say is the change in angular momentum is ##\Delta(I\omega)##.
Now you can find alpha is angular acceleration. Its is like acceleration.
##\alpha=\Delta\omega /\Delta t##
 
  • #15
Tejas Patel said:
Can anybody tell me how to calculate torque for rotating sweeper machine broom?
I assume that you want to know the torque needed to keep it turning once it has reached speed and is being used. The operating torque will depend on the contact pattern with the swept area, the velocity of travel and the friction between the brush and the swept surface.

The size of the bristles on the brush will have a significant effect. Use the biggest bristles that will do the job.

Review the marketing information from manufacturers of sweeping machines. Make a list of published motor HP and brush RPM. From that you can calculate torque since power is torque multiplied by RPM.
 
  • #16
Baluncore said:
I assume that you want to know the torque needed to keep it turning once it has reached speed and is being used. The operating torque will depend on the contact pattern with the swept area, the velocity of travel and the friction between the brush and the swept surface.

The size of the bristles on the brush will have a significant effect. Use the biggest bristles that will do the job.

Review the marketing information from manufacturers of sweeping machines. Make a list of published motor HP and brush RPM. From that you can calculate torque since power is torque multiplied by RPM.
Hello,

i am using it to clean solar panel, and my selected bristles dia is 0.3 mm also coefficient of sliding friction between solar panel and brush is 0.1 as per supplier data.
any specify calculation formula for same? Bcz i try as per post 12 but its value come too high.
please help me.
 
  • #17
Broom Dia is - 0.6 m. Weight - 150 Kg.

A quick estimate begins with 150kg * 9.8 = 1470. N
Coefficient of friction is 0.1 so force needed is 1470 * 0.1 = 147N

Diameter is 600mm therefore radius is 300mm = 0.3m.
Torque needed is 147.N * 0.3m = 44.1 Newton.metre
 
  • #18
Baluncore said:
Broom Dia is - 0.6 m. Weight - 150 Kg.

A quick estimate begins with 150kg * 9.8 = 1470. N
Coefficient of friction is 0.1 so force needed is 1470 * 0.1 = 147N

Diameter is 600mm therefore radius is 300mm = 0.3m.
Torque needed is 147.N * 0.3m = 44.1 Newton.metre
May be this start up torque, So can i need more torque to rotate it constant ?
 
  • #19
Tejas Patel said:
May be this start up torque, So can i need more torque to rotate it constant ?
44.1 Nm is an estimate of the continuous operating torque while being used. You may need more torque to start the rotation, but that will only be if you need to accelerate it quickly, or if it is started while it is in contact with a panel.
 

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