Torque exerted by a cylinder's weight

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SUMMARY

The discussion focuses on calculating the torque exerted by a cylinder's weight when held horizontally. The formula provided is T = (ρL(r²₄ - r¹₄) × (Δr)(ρ)(m) * 2π) / (60π(Δt)). Participants clarify that ρ represents density, and there is a question regarding the significance of the 60π(Δt) term when the stick is horizontal. The conversation emphasizes understanding the variables involved, particularly the differences between r₁ and r₂.

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24forChromium
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Imagine a person holding a stick horizontally, the stick is in the shape of a cylinder, with radius(r), length(L), and density(rho), consider the contacting area between the hand and the stick to be a point at the centre of the circular surface pointing toward the person, what is the torque exerted by the cylinder around the point of contact (as the pivot)?
 
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T = (pL(r24-r14) × ((change in r)(p)(m)) * 2pi)

All of that divided by

60pi*(change in time)
 
CentrifugalKing said:
T = (pL(r24-r14) × ((change in r)(p)(m)) * 2pi)

All of that divided by

60pi*(change in time)
Can you explain what is the difference between r_1 and r_2 please? Also, I am looking for the torque of the moments of time in which the stick is horizontal, so can I assume that I can ignore the 60pi*(change in time) part?

I assume that you meant ρ when you typed "p", is that what it is?
 

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