- #1

josh0916

- 1

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1. Can I use the assumption that the mass on the disc doesn't matter much for my calculation and use that weight (20,000lbs) for my I=(1/2)*m*r^2?

2. Is the 0.5 coefficient pretty conservative in general for a disc on a bearing?

If so, I am getting I=55778

T=I*a*(coefficient of friction) = 2920

HP = 1.668

This sound about right? Thanks for any help.