Torsoin pendulum with meter stick

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SUMMARY

The discussion centers on the oscillation period of a meter stick suspended from a thin wire, initially oscillating with a period of 6.0 seconds. After cutting the stick to a length of 70.0 cm, the new oscillation period is calculated using the formula T = T_0 * sqrt(I / I_0). The correct period for the shortened stick is determined to be 3.5 seconds, as confirmed by referencing an archived forum thread for additional insights.

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Homework Statement



A meter stick is hung at its center from a thin wire. It is twisted and oscillates with a period of 6.0 s. The meter stick is sawed off to a length of 70.0 cm. This piece is again balanced at its center and set in oscillation.

Homework Equations



T = 2PI / (omega) = 2PI * (sqrt(I/k)) where I = m.o.i and k =torsion constant

The Attempt at a Solution



I managed to get the value for the two period

T = T_0 * sqrt (I / I_0) where T_0 and I_0 are the initial parameters. The problem is the question does not state the I and I_0. I tried considering it to be a thin rod but failed. The correct answer is 3.5s.
 

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