Total forces acting downward on the plane

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The discussion focuses on determining the motion of a block on a slope by analyzing the forces acting on it. The total downward force, calculated as 150 + 100*9.81*sin(20) - 784, results in a negative value, indicating that the block is moving upward. It is clarified that the tension forces do not cancel when considering individual blocks, as they affect each block's motion differently. When analyzing the entire system, tension cancels out, showing it does not contribute to the overall motion. The conclusion is that the block slides up the ramp due to the net upward force.
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Homework Statement


I'm asked to find whether the object is moving or not
in this question , i was given the solution like this , i am wondering why the tension from 100kg to the roller(up) and the tension from point B to roller doesn't cancel each other?[/B]
Total force acting down the slope ignoring friction for the moment is

150 + 100*9.81*sin 20 - 784 = -299.3F_s = 0.2 *100 * 9.81 *cos(20) = 276.6N. Since the upward force is greater than this, the block is moving. Now we can use sliding friction in the sum of forces:

Total F = -299.3 + 0.2 x 100 x 9.81 x cos(20) = -299.3 + 184.4 = -114.9N. the minus sign says the sum of forces is upward, and the block slides up the ramp.

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You have to use static friction to find if the block is moving or not, you are using the kinetic friction!

For the tension, when you isolate one of the blocks, tension force acts on it. When you isolate the ENTIRE system, tension cancels itself because it does not contribute to the motion of the system as a whole.
 
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