Total Kinetic Energy: Man, Globe, Platform

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SUMMARY

The total kinetic energy of the system comprising a man, a globe, and a turntable is calculated using the formula K = 0.5Mv² + L²/(2I). In this scenario, the man swings a 1.5 kg globe at the end of a 0.7 m chain, completing a revolution every 3.4 seconds. The moment of inertia of the man and platform is 0.5 kgm², and the calculated total kinetic energy is 3.091 Joules. The angular velocity of the system is 2.71 rad/s, which is in the opposite direction to that of the globe.

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Homework Statement


A man stands at the center of a turntable that can rotate without friction. He then takes a 1.5 kg globe of the Earth and swings it around his head at the end of a 0.7 m long chain. The world revolves around him every 3.4 s, and the man and the platform have a moment of inertia of 0.5 kgm^2. The angular velocity is 2.71 rad/s in the opposite direction to that of the globe. What is the total Kinetic Energy of the man, the globe, and the platform?

Homework Equations


K = 0.5Mv^2 of the globe + L^2/(2I) of the platform

The Attempt at a Solution


K total = 0.5Mv^2 + L^2/(2I)
K total = 0.5(1.5)(0.7x2pi/3.4)^2 + (0.5x2.71)^2/(2x0.5) = 3.091J

Plz. help... I do not think my answer is right... mainly the equation part...
-Thanks a lot...
 
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