Total power of resistors in a circuit

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SUMMARY

The discussion focuses on calculating the total power of resistors in a circuit using the formula P=I²R. The user attempts to find the total power (PT) by summing the power across individual resistors (PR1, PR2, PR3, PR4, PR5) and applies Thevenin's theorem to simplify the circuit. The user correctly identifies the power for resistors PR1 and PR5, but struggles with the total power calculation, expecting a result of 312 W. The conversation highlights the importance of correctly applying Thevenin equivalents and using voltage across resistors to calculate power accurately.

PREREQUISITES
  • Understanding of electrical circuits and resistor configurations
  • Familiarity with Thevenin's theorem and its application
  • Knowledge of power calculations using P=I²R and P=U²/R
  • Ability to analyze circuit components and their interactions
NEXT STEPS
  • Study Thevenin's theorem in detail and its implications for circuit analysis
  • Learn advanced power calculation techniques for resistors in series and parallel
  • Explore circuit simulation tools like LTspice for practical applications
  • Review voltage and current relationships in complex circuits
USEFUL FOR

Electrical engineering students, circuit designers, and anyone involved in analyzing and calculating power in electrical circuits.

doktorwho
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Homework Statement


In this problem we are asked to calculate the total power of the resistors in the circuit below.
First.JPG

Homework Equations



##P=I^2R##

The Attempt at a Solution


My solution goes like this:
PT=PR1+PR2+PR3+PR4+PR5
I can find PR1 and PR5 immediately from the given current generators:
PR1=IG1^2*R1
PR5=IG2^2*R5
Second.JPG

Since i know those powers one i don't need the current generators and can transform the right and left sides to thevenin equivalents:
Clearly
ET1=-ET2
ET1=E1=24V and RT1=R1=12Ω (i hope i got this right)
Third.JPG

Forth.JPG

Now we can see that we have this type of situation. I transformed the resistor 3 as in the picture and can divide the circuits into 2 and the powers of the resistors will the sum of two.
Fifth.JPG

I will be solving the left one:
Re=R3R2/(R3+R2)=4Ω
I=ET1/(Re+R1) = 24/18 = 4/3 A
and the power of two element are P3'+P2=Re*(4/3)^2 and that times 2 is the total power.
Something is wrong here. The result should yield 312 W and i just don't get that. What is wrong?
 
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PR1 and PR5 are correct.

Now, what are the voltages across R2, R3 and R4 ? ( Forget about Thevenin and so on )
 
I'm not liking your Thevenin equivalents. In particular, I don't like the Thevenin Resistance value. What happens when you suppress both sources in the sub-circuit that you're converting?

I also think you're missing out on further opportunities to directly calculate powers in certain resistors. You should have a formula for power when you know the voltage across a resistor, as well as one for when you know the current through it.
 
Oh, how dumb of me. I have the voltage across R2 and R4 and it's 24V for the R2 and -24 for the R4 so the voltage across R3 is -48V right? If so the formula is ##P=\frac{U^2}{R}##
 
Hesch said:
PR1 and PR5 are correct.

Now, what are the voltages across R2, R3 and R4 ? ( Forget about Thevenin and so on )

gneill said:
I'm not liking your Thevenin equivalents. In particular, I don't like the Thevenin Resistance value. What happens when you suppress both sources in the sub-circuit that you're converting?

I also think you're missing out on further opportunities to directly calculate powers in certain resistors. You should have a formula for power when you know the voltage across a resistor, as well as one for when you know the current through it.
Is the above corrrect?
 
doktorwho said:
Oh, how dumb of me. I have the voltage across R2 and R4 and it's 24V for the R2 and -24 for the R4 so the voltage across R3 is -48V right? If so the formula is ##P=\frac{U^2}{R}##
Right.
 
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