Transformer copper loss calculation

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SUMMARY

The discussion focuses on calculating the copper loss of a transformer with a primary winding resistance of 125 Ohms and a secondary resistance of 0.7 Ohms, rated at 240V, 50Hz, and 28VA. The primary current is calculated as 1.92A using the formula I=V/R. The secondary current is derived from the VA rating, resulting in 2.33A at 12V. The copper loss formula is established as W = Ip² * Rp + Is² * Rs, where the correct values for Ip and Is must be used for accurate loss calculations.

PREREQUISITES
  • Understanding of transformer ratings, specifically VA ratings
  • Knowledge of Ohm's Law for calculating current (I=V/R)
  • Familiarity with the concept of copper loss in transformers
  • Ability to apply the copper loss formula W = Ip² * Rp + Is² * Rs
NEXT STEPS
  • Research the relationship between primary and secondary currents in transformers
  • Learn about the impact of turns ratio on copper and core losses
  • Study the significance of VA ratings in transformer applications
  • Explore detailed examples of copper loss calculations in various transformer configurations
USEFUL FOR

Electrical engineering students, transformer design engineers, and professionals involved in power systems and energy efficiency assessments will benefit from this discussion.

tommoturbo
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Hello guys have a little problem



see if anyone can help

Homework Statement



Q the primary winding resistance is 125Ohms, Secondary is 0.7ohms calulate the transformers copper loss at full load.



now the transformers name plate is 240V 50Hz 28VA the earlier question explains it is a step down transformer delivering 12V



Homework Equations




so primary Current = Vp/Rp 240/125 = 1.92A



now I am not sure what figures to use to calc the current in secondary winding at full load





i get values from 40A 38.4A



and using formula Full load current = VA rating/primary voltage i get .116A



i need Is value for copper loss formula



Copper loss W= Ip(sq)xRp+Is(sq)+Rs
Copper loss W= 1.92(sq)x125+Is(sq)+0.7 don't know the equation for secondary current Is














any help appreciated
 
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First of all, you're not calculating the primary current correctly. Hint: what does 28 VA mean?

Once you have that, remember that power in = power out to work out the secondary full-load current.
 
thanks for the reply but I am lost now.

not entirely sure what to do with the 28VA but thought it was used somehow to calc secondary current

thought i did the priomary current ok though
I=V/R 240/125


am i on the wrong track?
 
Very much so. Let's start at a more basic level, then:

What is VA? What does it mean and how is it calculated?
 
"The VA rating is the math formula used in determining the amperage at a given voltage."

So my secondary voltage of 12 volts from a 28VA transformer will produce 2.33 amps...?

e.g., 28 VA ÷ 12 Volts = 2.33 Amps. am i correct.
 
Right. Now, what do you know about the relationship of primary current to secondary current?
 
does this apply to the primary current also


primary voltage of 240volts from a 28VA transformer will produce .116 amps...

e.g., 28 VA ÷ 240 Volts = .116 Amps.

thanks for you help in this
 
You've got it! Now you can plug those values into I2R to find the primary and secondary copper watt losses.
 
Brilliant thanks for the advice

:)
 
  • #10
hey guys
i have a doubt
will turns ratio affect the amount of copper loss or core loss
i am a little bit confused in ds matr
 
  • #11
tommoturbo said:
Hello guys have a little problem
see if anyone can help

Homework Statement


Q the primary winding resistance is 125Ohms, Secondary is 0.7ohms calulate the transformers copper loss at full load.
now the transformers name plate is 240V 50Hz 28VA the earlier question explains it is a step down transformer delivering 12V

Insufficient data.

Is 12 VRMS the unloaded secondary voltage?
Is this an imaginary transformer with the unloaded primary power dissipation equal to zero?
I don't know if this one counts, but are we to pretend that 'full load' is a purely resistive load?
 
Last edited:

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