Transforming a Double Integral with Constant Function Along Parallel Lines

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Homework Help Overview

The discussion revolves around transforming a double integral involving a constant function along parallel lines, specifically within the context of a disk defined by the equation x² + y² ≤ 1. The original poster is tasked with proving a specific integral transformation without using polar coordinates.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the change of variables needed for the transformation, discussing the relationship between the variables and the function f. There is an emphasis on understanding the geometric interpretation of the transformation, particularly regarding rotations and the roles of the parameters u and v.

Discussion Status

Participants are actively engaging with the problem, proposing different substitutions and questioning the rationale behind their choices. Some guidance has been offered regarding the geometric interpretation of the transformation, but there remains uncertainty about the specifics of the substitutions and their implications.

Contextual Notes

Constraints include the prohibition of polar coordinates and the requirement to understand the transformation in terms of vector relationships and rotations. There is also a focus on the nature of the function f being constant along certain lines, which influences the choice of variables.

naggy
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I'm supposed to prove that

\int\int_{S}^{}\ f(ax + by + c) \, dA \ =2 \int_{-1}^{1} \sqrt{1 - u^2} f(u\sqrt{a^2 + b^2} + c) \, du

Where S is the disk x^2 + y^2 <= 1. It is also given that a^2 + b^2 is not zero

I can´t use polar coordinates and I can´t see how you simplify the surface S in any other way. What is the change of variable and why?
 
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It should be pretty clear from the formula what the change of variables should be, right? u*sqrt(a^2+b^2)+c=ax+by+c. So in vector terms u=(a,b).(x,y)/|(a,b)|. u is the dot product of (x,y) with the normalization of the vector (a,b). It's just a rotation of the unit disk so that f is a function only of u. Does that help?
 
Dick said:
It should be pretty clear from the formula what the change of variables should be, right? u*sqrt(a^2+b^2)+c=ax+by+c. So in vector terms u=(a,b).(x,y)/|(a,b)|. u is the dot product of (x,y) with the normalization of the vector (a,b). It's just a rotation of the unit disk so that f is a function only of u. Does that help?

I thought about that, it's sort of obvious, but then I can´t see what the other substitution is, that is

u = u(x,y)
v = v(x,y)

Now I know what to substitute for u, but not v.
 
Set v to be the dot product of (x,y) with a unit vector perpendicular to (a,b)/|(a,b)|. How about (-b,a)/|(a,b)|?
 
Dick said:
Set v to be the dot product of (x,y) with a unit vector perpendicular to (a,b)/|(a,b)|. How about (-b,a)/|(a,b)|?

WOw this works. I don´t really understand why. What do you mean that it is a rotation of the unit disk? What does that even mean? Normalization of the vector (a,b)?

How did you know the other parameter should be perpendicular to the first one?

I think you are parametrizing the functions with vectors, but can you treat the variables x and y as regular vectors like i,j and k?
 
The function f is constant along lines that are parallel to the line ax+by=0 (lines ax+by=C for C a constant). If you don't want to work with vectors and dot products then you can just make a choice of (u,v) by rotating (x,y) so that f is constant along one of those directions. A rotation looks like u=x*cos(t)-y*sin(t), v=x*sin(t)+y*cos(t), right? So a clever choice of angle t is the direction of the line ax+by=0. This means tan(t)=-a/b. If that's tan(t) then sin(t)=b/sqrt(a^2+b^2), cos(t)=-a/sqrt(a^2+b^2). If you start working this stuff out, you'll see you are lead back to the same transformation we've been talking about. I may have some details wrong, like getting u and v backwards, but you get the idea, right?
 

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