- #31
Transfrom scheme into eq. scheme with one EMF and one resistor.
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SUMMARY
The discussion focuses on transforming a circuit scheme into an equivalent scheme featuring one electromotive force (EMF) and one resistor. The circuit includes resistors R1 (7 Ohms), R2 (5 Ohms), R3 (1 Ohm), and R4 (3 Ohms), with current J1 (1 A) and EMFs E1 (8 V) and E2 (4 V). Participants emphasize the importance of finding the Thevenin equivalent by disabling sources and calculating the open circuit voltage at points a-b, ultimately leading to the equivalent resistance. The final Thevenin equivalent circuit is established with a voltage of 1.6 V and a resistance of 0.875 Ohms.
PREREQUISITES- Understanding of Thevenin's theorem and its application in circuit analysis.
- Familiarity with Kirchhoff's Voltage Law (KVL) for loop analysis.
- Basic knowledge of series and parallel resistor configurations.
- Proficiency in using circuit simulation tools like Mathcad for solving equations.
- Study Thevenin's theorem in-depth to understand its practical applications in circuit design.
- Learn how to apply Kirchhoff's Voltage Law (KVL) to complex circuits for loop analysis.
- Explore circuit simulation software such as LTspice or Multisim for visualizing circuit behavior.
- Research methods for calculating equivalent resistance in circuits with multiple sources and components.
Electrical engineering students, circuit designers, and anyone involved in analyzing and simplifying electrical circuits using Thevenin's theorem.
- #32
gneill
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One of the wires is redundant. You can't have less resistance than no resistance!
Remove one of them and solve for the net resistance across a-b.
Last edited:
- #33
- #34
gneill
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Okay. Now put this Thevenin resistance in series with the Thevenin voltage source that you calculated before. That should be your final circuit, the Thevenin Equivalent for the original.
- #35
- #36
gneill
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Yes. Be sure that you pay attention to the polarity of the voltage source. Remember that you found a negative value for E, making point a negative with respect to b.
- #37
builder_user
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- 0
Remember that you found a negative value for E, making point a negative with respect to b.
I need to change the direction of E?
But E>0 because I3>0 & R3>0.
One of the tasks is done(I don't sure in this tense form)(another task is node potential method(only 2 nodes in the circuit so I try to make on my own(with rare success)).Thanks for your help.
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