Transfrom scheme into eq. scheme with one EMF and one resistor.

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Homework Help Overview

The discussion revolves around transforming a circuit schematic into an equivalent circuit with one EMF and one resistor, focusing on Thevenin equivalents. Participants are exploring configurations of resistors, current sources, and voltage sources within the circuit.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants discuss the identification of series and parallel configurations, the process of disabling sources to find Thevenin resistance, and the implications of current and voltage measurements. Questions arise about specific circuit transformations and the interpretation of voltage signs.

Discussion Status

The discussion is active with participants sharing equations, questioning assumptions, and providing hints. Some guidance has been offered regarding the Thevenin equivalent process, but there is no explicit consensus on the final approach or values.

Contextual Notes

Participants are working under constraints related to homework rules, including the need to transform the circuit without providing complete solutions. There are indications of confusion regarding the application of circuit laws and the interpretation of results.

  • #31


The new circuit is pic.1

What do I need to do with this two branches?OH!It's not R2.It's R3
 

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  • #32


One of the wires is redundant. You can't have less resistance than no resistance!
Remove one of them and solve for the net resistance across a-b.
 
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  • #33


Rn=(R1*R3)/(R3+R1)

And new circuit is
 

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  • #34


Okay. Now put this Thevenin resistance in series with the Thevenin voltage source that you calculated before. That should be your final circuit, the Thevenin Equivalent for the original.
 
  • #35


The final circuit is...
E=U=1.6 V
Rn=0.875 Ohms
 

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  • #36


Yes. Be sure that you pay attention to the polarity of the voltage source. Remember that you found a negative value for E, making point a negative with respect to b.
 
  • #37


Remember that you found a negative value for E, making point a negative with respect to b.

I need to change the direction of E?
But E>0 because I3>0 & R3>0.

One of the tasks is done(I don't sure in this tense form)(another task is node potential method(only 2 nodes in the circuit so I try to make on my own(with rare success)).Thanks for your help.
 

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