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Hi, I have been given a question which involves analysis of a series RC circuit. The system in question has a 4Ω resistor in series with a 1000μF Capacitor (the capacitor is to be considered as completely uncharged before t=0). There is a 12V supply in the circuit. At t=0, a switch is closed to complete the circuit. I have been asked to calculate the following and was wondering if someone could confirm whether or not my answers are correct;
i. - initial (t=0) current in the circuit.
ii.- initial voltage across the capacitor
iii- final voltage in the capacitor
iv- time constant of the circuit
v - current in the circuit at 6ms
vi - final energy stored in the capacitor
Answers
i. initial (t=0) current in circuit = V/R = 12/4 = 3.0A
ii. Initial voltage across the capacitor = 0V (as Capacitor is uncharged before switch is closed at t=0)
iii. final voltage in capacitor = V = 12V.
iv time constant of the circuit = ζ = CR = 1000 x 10-6 * 4 = 4mS or 0.004S
v. current in circuit at t=6ms = i(t) = Ioe(-t/ζ)
this = 3.0e-(0.006/0.004) = 0.67A
vi - final energy stored in capacitor = E = (CV2/2) = (1000x10-6 * 122)/2 = 0.072J
Any feedback would be greatly appreciated! :)
i. - initial (t=0) current in the circuit.
ii.- initial voltage across the capacitor
iii- final voltage in the capacitor
iv- time constant of the circuit
v - current in the circuit at 6ms
vi - final energy stored in the capacitor
Answers
i. initial (t=0) current in circuit = V/R = 12/4 = 3.0A
ii. Initial voltage across the capacitor = 0V (as Capacitor is uncharged before switch is closed at t=0)
iii. final voltage in capacitor = V = 12V.
iv time constant of the circuit = ζ = CR = 1000 x 10-6 * 4 = 4mS or 0.004S
v. current in circuit at t=6ms = i(t) = Ioe(-t/ζ)
this = 3.0e-(0.006/0.004) = 0.67A
vi - final energy stored in capacitor = E = (CV2/2) = (1000x10-6 * 122)/2 = 0.072J
Any feedback would be greatly appreciated! :)