Trickey projectile motion question

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SUMMARY

The discussion centers on a projectile motion problem involving a shell fired from a cliff of height 'h' with an initial speed 'U'. The maximum horizontal distance the shell can travel before hitting the sea is derived as (U/g)(U^2 + 2gh)^(1/2). Additionally, the angle for achieving this maximum distance is given by tan^(-1){U/((U^2 + 2gh)^(1/2))}. The problem emphasizes the importance of separating horizontal and vertical components of motion and suggests the use of trigonometric substitutions for solving the equations.

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trickey projectile motion question!

Homework Statement



1. (i)A shell is fired with speed 'U' from a point on a cliff of height 'h' above sea level. Show that the greatest horizontal distance that the shell can travel before reaching the sea is

(U/g)(U^2 + 2gh)^(1/2)

(ii)and that the angle for maximum distance is

tan^(-1){U/((U^2 + 2gh)^(1/2))}


Homework Equations


also given in the question is a general projectile equation

y= (x)(tan(a) - {(g)(x^2)}/{(2)(U^2)((cos(a))^2)}


The Attempt at a Solution



Ive repeatedly attempted this with little success, i think the key is use of trigonometric substitutions, but I am not sure. Please Help!
 
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Well for the first part I assume the projectile is fired horizontally. The maximum distance it can travel depends on its travel time. The travel time all depends on the height of the cliff. With these questions you need to consider horizontal and vertical components separately.
 

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