1/ [e^x (1-e^(-2x))^1/2]
integration by parts
The Attempt at a Solution
First I split up the integral so it would be (1/e^-x)[(1/(1-e^-2x)^1/2]
Then I set u=e^-x, dv= (1-e^-2x)^-1/2
For my v I got 2(1-e^-2x)^1/2 but I don't know how to go about with the e^-2x, as in how to finish solving for the v-part.
I tried u-substitution and I get another term in the denominator. Then when I tried to differentiate the answer I originally got for v, I did not have anything in the denominator... can anyone help?