Trig Substitutions Homework: "Uh... why?

  • Thread starter Thread starter nhmllr
  • Start date Start date
  • Tags Tags
    Trig
Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
3 replies · 2K views
nhmllr
Messages
183
Reaction score
1

Homework Statement


This is only a step in a bigger example problem on trig substitution
2/3 *x2 = sin2[tex]\theta[/tex]
[tex]\sqrt{}2/3[/tex] * x =sin[tex]\theta[/tex]
[tex]\theta[/tex] = arcsin([tex]\sqrt{}2/3[/tex] * x)
and
x = [tex]\sqrt{}3/2[/tex] * sin[tex]\theta[/tex]
This makes sense
Then I saw
dx / d[tex]\theta[/tex] = [tex]\sqrt{}3/2[/tex] * cos[tex]\theta[/tex]
Uh... why?

Homework Equations


Regular trig equations


The Attempt at a Solution


I have no idea
 
Physics news on Phys.org
What exactly is your question? Why is the derivative of sine, cosine?
 
Sourabh N said:
What exactly is your question? Why is the derivative of sine, cosine?

Yeah
 
nhmllr said:

Homework Statement


This is only a step in a bigger example problem on trig substitution
2/3 *x2 = sin2[tex]\theta[/tex]
[tex]\sqrt{}2/3[/tex] * x =sin[tex]\theta[/tex]
You can't conclude what you have above. This is what it should be.
[tex]\sqrt{2/3} * x = \pm sin (\theta)[/tex]

nhmllr said:
[tex]\theta[/tex] = arcsin([tex]\sqrt{}2/3[/tex] * x)
and
x = [tex]\sqrt{}3/2[/tex] * sin[tex]\theta[/tex]
This makes sense
Then I saw
dx / d[tex]\theta[/tex] = [tex]\sqrt{}3/2[/tex] * cos[tex]\theta[/tex]
Uh... why?

Homework Equations


Regular trig equations


The Attempt at a Solution


I have no idea