- #1
AznBoi
- 471
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I just came across a problem that wants you to solve for csc of an angle in radians... However, I'm confused about the answer given.
Here is the problem:
Find the csc when t=-2pi/3, which is equivalent to -120 degrees right?
I got -2sqrt.(3)/3 but the answer in the back is -2sqrt.(3)/2 Why is it a 2 instead of a three??
The sin is -sqrt.(3)/2 and it is correct, so shouldn't the csc be the reciprocal of sin?? 1/sin theta?? so 1/(-2sqrt.(3)/3)?
Thanks!
Here is the problem:
Find the csc when t=-2pi/3, which is equivalent to -120 degrees right?
I got -2sqrt.(3)/3 but the answer in the back is -2sqrt.(3)/2 Why is it a 2 instead of a three??
The sin is -sqrt.(3)/2 and it is correct, so shouldn't the csc be the reciprocal of sin?? 1/sin theta?? so 1/(-2sqrt.(3)/3)?
Thanks!