Trigonometric identities for integral problem

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SUMMARY

The integral \(\int \frac{ab}{a^2 \cos^2 t + b^2 \sin^2 t} dt\) from 0 to \(2\pi\) evaluates to \(2\pi\). Despite initial challenges with trigonometric identities and algebraic manipulations, the solution was confirmed using a calculator. The discussion highlights the importance of recognizing when numerical methods can validate analytical results.

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Students studying calculus, particularly those tackling integral problems involving trigonometric functions, and educators seeking to enhance their teaching methods in this area.

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Homework Statement


I have this integral to solve:
\int \frac{ab}{a^2 cos^2 t + b^2 sin^2 t} dt

The limits are 0 to 2*pi.

Homework Equations





The Attempt at a Solution


I've tried using trigonometric identities, trigonometric substitution... and many kinds of algebraic manipulations but I can't do it! I'm beginning to think it can't be done analytically but I doubt it because my professor wants us to prove it is equal to something else which I found is 2*pi. I used my calculator to do the integration and I did get 2*pi, so at least I know what it is equal to. However I don't seem to get anywhere trying to solve it. Please help!

Thanks.
 
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It looks like latex is acting up (maybe just for me?). You might want to just write out the code. Most of us will be able to read it anyhow.
 


I think if you click over the red text you see the latex code. Anyway here it is...
So it's an integral of: {ab} / {a^2 cos^2 t + b^2 sin^2 t} with respect to t.
From t=0 to 2*pi
 


Nevermind, I solved the problem.
 

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