Trigonometry - half angles problems

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Homework Help Overview

The discussion revolves around a trigonometry problem involving half-angle and double-angle formulas. The original poster has expressed cos(2x) in terms of sin(x) and is now attempting to solve the equation cos(x) + 3sin(x/2) = 2, seeking guidance on how to handle the half-angle component.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between full angles and half angles, with some suggesting the use of substitution to simplify the equation. There is a focus on how to eliminate the half-angle term and the potential use of a new variable for clarity.

Discussion Status

Participants are actively engaging with the problem, offering suggestions for substitution and exploring the implications of those substitutions. There is a recognition of the need for a refresher on handling half angles, indicating a productive direction in the discussion.

Contextual Notes

Some participants note the difficulty in framing the problem within the expected format, highlighting the challenge of addressing half-angle concepts in the context of the given equation.

paul18
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Homework Statement


Previous part of the question I have solved:
Express cos(2x) in terms of sin(x):

I got this answer:
cos(2x)=1-2sin2(x)

Hence or otherwise solve the equation
cos(x) + 3sin(x/2) = 2


Homework Equations


Double angle formulae:
cos(2x)=cos(2x) - sin(2x)
sin(2x)=2sin(x)cos(x)


The Attempt at a Solution


So basically I'm doing revision on trig, and I know I've come across this problem before, where you are presented with a full angle and a half angle, but I have failed to find an example. It's something to do with halving a double angle formula I think but I can't even start it. How do I get rid of the half angle? I know I should show an attempt, but I can't even start it off. Just a refresher on how to remove half angles would be great thanks :)
(Yes i have read the rules but this problem is difficult to put into that format properly)
 
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paul18 said:

Homework Statement


Previous part of the question I have solved:
Express cos(2x) in terms of sin(x):

I got this answer:
cos(2x)=1-2sin2(x)

Hence or otherwise solve the equation
cos(x) + 3sin(x/2) = 2


Homework Equations


Double angle formulae:
cos(2x)=cos(2x) - sin(2x)
sin(2x)=2sin(x)cos(x)


The Attempt at a Solution


So basically I'm doing revision on trig, and I know I've come across this problem before, where you are presented with a full angle and a half angle, but I have failed to find an example. It's something to do with halving a double angle formula I think but I can't even start it. How do I get rid of the half angle? I know I should show an attempt, but I can't even start it off. Just a refresher on how to remove half angles would be great thanks :)
(Yes i have read the rules but this problem is difficult to put into that format properly)

If the first part read cos(2z) in terms of sin(z), what would your answer be? Then substitute z for x/2 in the second question
 
paul18 said:

Homework Statement


Previous part of the question I have solved:
Express cos(2x) in terms of sin(x):

I got this answer:
cos(2x)=1-2sin2(x)

Hence or otherwise solve the equation
cos(x) + 3sin(x/2) = 2


Homework Equations


Double angle formulae:
cos(2x)=cos(2x) - sin(2x)
sin(2x)=2sin(x)cos(x)

Note that x = 2 times (x/2). It may be helpful if you substitute another variable, say y, in for x/2. What would x equal? What does this equation:
cos(x) + 3sin(x/2) = 2
look like with the substitutions?
 
eumyang said:
Note that x = 2 times (x/2). It may be helpful if you substitute another variable, say y, in for x/2. What would x equal? What does this equation:
cos(x) + 3sin(x/2) = 2
look like with the substitutions?

cos(2y) + 3sin(y) = 2.
Thanks very much that's what I needed a refresher on :)
 

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