- #1
basty
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- 0
For the triangle shown in the below image,
##\sin 60° = \frac{opposite}{hypotenuse} = \frac{y}{r}##
##\sin 30° = \frac{opposite}{hypotenuse} = \frac{x}{r}##
The questions are:
1. What is the opposite and hypotenuse of sin 90°?
2. I am guessing that the opposite and hypotenuse of sin 90 is
r and y respectively so that ##\sin 90° = \frac{opposite}{hypotenuse} = \frac{r}{y}##.
Why sin 90° = 1?
##\sin 60° = \frac{opposite}{hypotenuse} = \frac{y}{r}##
##\sin 30° = \frac{opposite}{hypotenuse} = \frac{x}{r}##
The questions are:
1. What is the opposite and hypotenuse of sin 90°?
2. I am guessing that the opposite and hypotenuse of sin 90 is
r and y respectively so that ##\sin 90° = \frac{opposite}{hypotenuse} = \frac{r}{y}##.
Why sin 90° = 1?