Triple Integral Evaluation: Where Did I Go Wrong?

[-EquinoX-]

Homework Statement

http://img19.imageshack.us/img19/2559/triple.th.jpg

Homework Equations

The Attempt at a Solution

I get 16pi/3 (sqrt(2) -1) as the final result, but when I input the answer to the computer, it doesn't accept it. Am I doing a wrong integration/calculation anywhere? I double checked and I can't to find anything wrong.

 

[gabbagabbahey]

It seems that when you multiplied by 2pi, you said 16/3* 2pi=16pi/3...that's not really true is it?

 

[-EquinoX-]

oh so it should be 32pi/3 then.. thanks for pointing out the silly mistake

 

[foxjwill]

You went from
$$-\frac{1}{3}\left(4^{3}{2}-8^{3}{2})-\frac{8}{3}$$
to
$$\frac{16}{3}(\sqrt{2}-1)$$
instead of
$$\frac{8}{3}(2\sqrt{2}-1)$$