Triple Integral in Cylindrical Coordinates

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daveyman
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Homework Statement


Find the mass and center of mass of the solid S bounded by the paraboloid [tex]z=4x^2+4y^2[/tex] and the plane [tex]z=a\;\;(a>0)[/tex] if S has constant density K.


Homework Equations


In cylindrical coordinates, [tex]x^2+y^2=r^2[/tex].


The Attempt at a Solution


In order to find the mass, I tried
[tex]\int _0^{2\pi }\int _0^a\int _0^{\frac{\sqrt{z}}{2}}K\;drdzd\theta[/tex]
This didn't seem to work, though.
 
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daveyman said:
… I tried
[tex]\int _0^{2\pi }\int _0^a\int _0^{\frac{\sqrt{z}}{2}}K\;drdzd\theta[/tex]
This didn't seem to work, though.

Hi daveyman! :smile:

Hint: the volume element isn't drdzdθ. :wink:
 
Okay, so this is the mass:

[tex]\int _0^{2\pi }\int _0^a\int _0^{\frac{\sqrt{z}}{2}}\text{Kr}\;\;drdzd\theta = \frac{1}{8} a^2 K \pi[/tex]
 
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Now that I have the mass (m), I want to find the r component of the center of mass. I tried

[tex]\frac{1}{m}\int _0^{2 \pi }\int _0^a\int _0^{\frac{\sqrt{z}}{2}}K r^2drdzd\theta[/tex]

This is incorrect. What am I doing wrong?
 
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daveyman said:
Okay, so now that I have the mass (m), I want to find the r component of the center of mass. I tried

[tex]\frac{1}{m}\int _0^{2 \pi }\int _0^a\int _0^{\frac{\sqrt{z}}{2}}K r^2drdzd\theta[/tex]

This is incorrect. What am I doing wrong?

That should come out as 0, which is the r component of the centre of mass. :wink:
 
Mathematica is telling me that this integral is not equal to zero. Have I made a mistake?
I've included the output as an attachment.
 

Attachments

daveyman said:
Mathematica is telling me that this integral is not equal to zero. Have I made a mistake?
I've included the output as an attachment.

ah … just realized … you can't do centre of mass that way in cylindrical coordinates … you'd have to convert to x and y coordinates first.

(but the z coordinate will be ok :smile:)
 
tiny-tim said:
ah … just realized … you can't do centre of mass that way in cylindrical coordinates … you'd have to convert to x and y coordinates first.

(but the z coordinate will be ok :smile:)

Right, that makes sense. So how can I solve for the r and theta components in cylindrical coordinates? I know qualitatively that they should be zero, but how do I show this mathematically?
 
daveyman said:
Right, that makes sense. So how can I solve for the r and theta components in cylindrical coordinates? I know qualitatively that they should be zero, but how do I show this mathematically?

I think you're perfectly entitled to say that it's obvious. :smile:

(btw, if r is zero, then θ is meaningless :wink:)
 
tiny-tim said:
(btw, if r is zero, then θ is meaningless :wink:)

Very true. I think that's it. Thank you!