# Triple Integral in Cylindrical Coordinates

## Homework Statement

Find the mass and center of mass of the solid S bounded by the paraboloid $$z=4x^2+4y^2$$ and the plane $$z=a\;\;(a>0)$$ if S has constant density K.

## Homework Equations

In cylindrical coordinates, $$x^2+y^2=r^2$$.

## The Attempt at a Solution

In order to find the mass, I tried
$$\int _0^{2\pi }\int _0^a\int _0^{\frac{\sqrt{z}}{2}}K\;drdzd\theta$$
This didn't seem to work, though.

tiny-tim
Homework Helper
… I tried
$$\int _0^{2\pi }\int _0^a\int _0^{\frac{\sqrt{z}}{2}}K\;drdzd\theta$$
This didn't seem to work, though.

Hi daveyman! Hint: the volume element isn't drdzdθ. Okay, so this is the mass:

$$\int _0^{2\pi }\int _0^a\int _0^{\frac{\sqrt{z}}{2}}\text{Kr}\;\;drdzd\theta = \frac{1}{8} a^2 K \pi$$

Last edited:
Now that I have the mass (m), I want to find the r component of the center of mass. I tried

$$\frac{1}{m}\int _0^{2 \pi }\int _0^a\int _0^{\frac{\sqrt{z}}{2}}K r^2drdzd\theta$$

This is incorrect. What am I doing wrong?

Last edited:
tiny-tim
Homework Helper
Okay, so now that I have the mass (m), I want to find the r component of the center of mass. I tried

$$\frac{1}{m}\int _0^{2 \pi }\int _0^a\int _0^{\frac{\sqrt{z}}{2}}K r^2drdzd\theta$$

This is incorrect. What am I doing wrong?

That should come out as 0, which is the r component of the centre of mass. Mathematica is telling me that this integral is not equal to zero. Have I made a mistake?
I've included the output as an attachment.

#### Attachments

• Output.pdf
81.3 KB · Views: 163
tiny-tim
Homework Helper
Mathematica is telling me that this integral is not equal to zero. Have I made a mistake?
I've included the output as an attachment.

ah … just realised … you can't do centre of mass that way in cylindrical coordinates … you'd have to convert to x and y coordinates first.

(but the z coordinate will be ok )

ah … just realised … you can't do centre of mass that way in cylindrical coordinates … you'd have to convert to x and y coordinates first.

(but the z coordinate will be ok )

Right, that makes sense. So how can I solve for the r and theta components in cylindrical coordinates? I know qualitatively that they should be zero, but how do I show this mathematically?

tiny-tim
Homework Helper
Right, that makes sense. So how can I solve for the r and theta components in cylindrical coordinates? I know qualitatively that they should be zero, but how do I show this mathematically?

I think you're perfectly entitled to say that it's obvious. (btw, if r is zero, then θ is meaningless )

(btw, if r is zero, then θ is meaningless )

Very true. I think that's it. Thank you!