# Triple integral with cylindrical coordinates

1. Oct 27, 2009

### MasterWu77

1. The problem statement, all variables and given/known data

Use cylindrical coordinates to evaluate the triple integral

$$\int$$$$\int$$$$\int$$ $$\sqrt{x^2+y^2}$$ dV in region E

where E is the solid bounded by the circular paraboloid z=9-(x^2+y^2) and the xy-plane.

2. Relevant equations

knowing that x = rcos$$\theta$$
y= rsin$$\theta$$
z=z
for a coordinates in clindrical

3. The attempt at a solution

I'm not sure how to get the bounds of integration for this problem. I know it has something to do with the paraboloid given but I am not very good at drawing such a figure. I do understand that you need to change the x and y into xcos and ysin in order to integral the problem. any help would be greatly appreciated!

2. Oct 28, 2009

### lanedance

hey MaterWu77, start by transforming your integrand and bounding surface into cylindircal coordinates, things should simplify a fair bit

3. Oct 28, 2009

### Staff: Mentor

Another relevant equation, and one you didn't show, is r2 = x2 + y2.

In cylindrical coordinates, dV can be represented as dz r dr d$\theta$. Take note of that factor of r.

You region E is such that 0 <= z <= 9 - (x2 + y2), 0 <= r <= 3, and 0 <= $\theta$ <= $2\pi$.

The resulting integral in cylindrical form looks like this. The question marks are placeholders that you need to fill in.

$$\int_{\theta = ?}^{?} \int_{r = ?}^? \int_{z = 0}^? ?~dz~r~dr~d\theta$$

Because of the symmetry of your integrand and the region E, you can integrate the part in the first quadrant and multiply your result by 4.

4. Oct 28, 2009

### MasterWu77

ok i understand how to get the bounds of integration. would the function that i am integrating be r^2 which would come from the $$\sqrt{x^2+y^2}$$ ?

5. Oct 28, 2009

### Staff: Mentor

No, it would be sqrt(r^2), which is just r for your region. There is also the r in dz r dr d(theta). Wasn't sure if you were including that one as well.

6. Oct 28, 2009

### MasterWu77

yes i was including the r from the dz r dr d(theta) to get the r^2

7. Oct 28, 2009

### Staff: Mentor

So this is what you have:
$$\int_{\theta = ?}^{?} \int_{r = ?}^? \int_{z = 0}^? r^2~dz~dr~d\theta$$
Do you have the limits of integration worked out?

8. Oct 28, 2009

### MasterWu77

yes i do! and i have the rest of the problem worked out so thanks a lot for helping me out!