Triple integral with cylindrical coordinates

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Homework Help Overview

The problem involves evaluating a triple integral using cylindrical coordinates, specifically the integral of the function \(\sqrt{x^2+y^2}\) over a solid region bounded by a circular paraboloid and the xy-plane.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss transforming the integrand and bounding surfaces into cylindrical coordinates, questioning how to determine the bounds of integration based on the given paraboloid.

Discussion Status

Some participants have provided guidance on the transformation process and the representation of the volume element in cylindrical coordinates. There is an ongoing exploration of the limits of integration, with some participants confirming their understanding of the necessary transformations.

Contextual Notes

Participants note the need to visualize the region defined by the paraboloid and the xy-plane, as well as the implications of symmetry in the integrand and region for simplifying the integral.

MasterWu77
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Homework Statement



Use cylindrical coordinates to evaluate the triple integral

[tex]\int[/tex][tex]\int[/tex][tex]\int[/tex] [tex]\sqrt{x^2+y^2}[/tex] dV in region E

where E is the solid bounded by the circular paraboloid z=9-(x^2+y^2) and the xy-plane.

Homework Equations



knowing that x = rcos[tex]\theta[/tex]
y= rsin[tex]\theta[/tex]
z=z
for a coordinates in clindrical

The Attempt at a Solution



I'm not sure how to get the bounds of integration for this problem. I know it has something to do with the paraboloid given but I am not very good at drawing such a figure. I do understand that you need to change the x and y into xcos and ysin in order to integral the problem. any help would be greatly appreciated!
 
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hey MaterWu77, start by transforming your integrand and bounding surface into cylindircal coordinates, things should simplify a fair bit
 
Another relevant equation, and one you didn't show, is r2 = x2 + y2.

In cylindrical coordinates, dV can be represented as dz r dr d[itex]\theta[/itex]. Take note of that factor of r.

You region E is such that 0 <= z <= 9 - (x2 + y2), 0 <= r <= 3, and 0 <= [itex]\theta[/itex] <= [itex]2\pi[/itex].

The resulting integral in cylindrical form looks like this. The question marks are placeholders that you need to fill in.

[tex]\int_{\theta = ?}^{?} \int_{r = ?}^? \int_{z = 0}^? ?~dz~r~dr~d\theta[/tex]

Because of the symmetry of your integrand and the region E, you can integrate the part in the first quadrant and multiply your result by 4.
 
ok i understand how to get the bounds of integration. would the function that i am integrating be r^2 which would come from the [tex]\sqrt{x^2+y^2}[/tex] ?
 
No, it would be sqrt(r^2), which is just r for your region. There is also the r in dz r dr d(theta). Wasn't sure if you were including that one as well.
 
yes i was including the r from the dz r dr d(theta) to get the r^2
 
So this is what you have:
[tex]\int_{\theta = ?}^{?} \int_{r = ?}^? \int_{z = 0}^? r^2~dz~dr~d\theta[/tex]
Do you have the limits of integration worked out?
 
yes i do! and i have the rest of the problem worked out so thanks a lot for helping me out!
 

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