# Trouble evaluating the integral for a rational function

## Homework Statement

i've tried many partial fraction methods but none of y answers are correct in the end, please help me evaluate the integral for f(x)= (10x+2)/(x-5)(x^2 + 1)

## Homework Equations

there are no relevant equations given

## The Attempt at a Solution

A/x-5 + Bx+C/x^2 +1

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rock.freak667
Homework Helper
So now you have

$$\frac{A(x^2+1)+(Bx+C)(x-5)}{(x-5)(x^2+1)}= \frac{10x+2}{(x-5)(x^2+1)}$$

So equating the numerators

A(x^2+1)+(Bx+C)(x-5)= 10x+2 for all values of x.

Try putting suitable values of x which will eliminate most of the constants. For example, x=5 will help you get A.