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This lemma the book states, I can't make sense of it.
Lemma: If a,b\in Z and b > 0, there exist q,r \in Z such that a = qb + r with 0 \leq r < b.
Proof: Consider the set of all integers of the form a-xb with x \in Z. This set includes positive elements. Let r = a - qb be the least nonnegative element in this set. We claim that 0\leq r < b. If not, r = a - qb \geq b and so 0\leq a-(q+1)b<r, which contradicts the minimality of r.
Can someone help explain this to me? Why can't a = 3, and b = 8. Then no q,r could exist so that r is less than b, right?
Lemma: If a,b\in Z and b > 0, there exist q,r \in Z such that a = qb + r with 0 \leq r < b.
Proof: Consider the set of all integers of the form a-xb with x \in Z. This set includes positive elements. Let r = a - qb be the least nonnegative element in this set. We claim that 0\leq r < b. If not, r = a - qb \geq b and so 0\leq a-(q+1)b<r, which contradicts the minimality of r.
Can someone help explain this to me? Why can't a = 3, and b = 8. Then no q,r could exist so that r is less than b, right?