Troubleshooting nuclear decay, electron binding energies, internal contributions

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SUMMARY

This discussion focuses on the selection of electron binding energy shells in nuclear decay analysis, specifically addressing the use of K and L2 shells. The participants clarify that L2 is included despite being below 20 keV, suggesting that the expression for electron energy is ΔE - B(L). They also highlight potential typographical errors in the original solution, indicating that L1 should be K and L2 should simply be L. Furthermore, the value B(L)_{Hg} = 14.2087 keV is proposed to be a weighted average of the L1, L2, and L3 levels.

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  • Knowledge of energy levels in atomic physics
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  • Study the differences between K, L1, L2, and L3 energy levels
  • Examine the significance of energy thresholds in particle physics
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Graham87
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How do you know which binding energy shell to use? In the solution it uses K and L2. Why specifically L2 and not L3 or L1 for example?

And what should I do with the information to omit electrons lower than 20kev? I initially thought that meant to omit the electron binding energies lower than 20kev. But L2 which is lower than 20kev is included, so which expression represents electron energy? If it is ΔE - B(L) then shouldn’t L3 be included since it also has a higher energy than 20kev?

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My guess is that there are some typos as indicated below:
1683822652238.png

The ##L_1## should be ##K## and the ##L_2##'s should just be ##L##. This corresponds with the given binding energies:

1683822987537.png


Perhaps the value ##B(L)_{Hg} = 14.2087## keV is a weighted average over the ##L_1##, ##L_2##, and ##L_3## levels.

I'm not sure about the 20 keV restriction. Since ##\overline E_\beta##, ##B(K)_{Hg}## and ##B(L)_{Hg}## are all in the hundreds of keV, there doesn't appear to be any need to worry about requiring the electrons to have an energy greater than 20 keV.
 
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