(True/False) Basic Probability Theory

AI Thread Summary
The discussion revolves around the interpretation of basic probability theory concerning three events defined by the outcomes of tossing a fair coin. The claim that P(Z) equals P(X) + P(Y) is deemed false, as P(Z) represents the probability of obtaining exactly 600 heads, while P(X) and P(Y) pertain to different outcomes. Participants clarify that the union of two distinct events allows for the sum of their probabilities only when the events do not overlap. The conversation emphasizes the importance of correctly applying probability rules, particularly in distinguishing between overlapping and non-overlapping events. Understanding these distinctions is crucial for accurate probability calculations.
rela
Messages
17
Reaction score
0
Dear all,

I have a question.

Suppose we have 3 events X,Y,Z defined as having 200 heads, 400 heads & 600 heads obtained in tossing a fair coin for 800 times.

Then, P(Z)=P(X+Y)=P(600)=P(200+400)=P(X)+P(Y)=P(200)+P(400)

The answer is false but I view it otherwise. My argument is based on the idea of the union of 2 events -> P(X U Y) =P(X) + P(Y). Following this line of reasoning, why is the above statement not considered true?

Please kindly elaborate and direct me to the right understanding level.

Thanks in advance.

Regards
Rela
 
Physics news on Phys.org
Hi Rela! :smile:

P(Z) is the probability of exactly 600 heads …

in full, P(Z) = P({600 heads and 200 tails}) …

so is the statement P({600 heads and 200 tails}) = P({400 heads and 400 tails} U {200 heads and 600 tails}) true or false or meaningless? :wink:
 
Hi Tim,

Many thanks for your prompt revert.

Hmmm...It looks kinda meaningless to me. But I'm just perturbed by the fact that there exists such a rule in which the probability of the union of 2 statistically events A & B is the the sum of their individual probabilities (i.e P(AUB)=P(A)+P(B).

I just feel that I could apply this rule to the problem statement defined earlier since it makes sense mathematically.

Are you able to elaborate more on the circumstance in which I could apply the above rule correctly then?

Regards
Rela
 
Hi Rela! :smile:
rela said:
Hmmm...It looks kinda meaningless to me.

Yes, that's right … it's meaningless! :biggrin:
But I'm just perturbed by the fact that there exists such a rule in which the probability of the union of 2 statistically events A & B is the the sum of their individual probabilities (i.e P(AUB)=P(A)+P(B).

The probability of the union of 2 distinct (non-overlappping) events A & B is the the sum of their individual probabilities.

(and the probability of the intersection of 2 independent events A & B is the the product of their individual probabilities :wink:)
I just feel that I could apply this rule to the problem statement defined earlier since it makes sense mathematically.

Are you able to elaborate more on the circumstance in which I could apply the above rule correctly then?

yes … you could use the rule if X is exactly 200 heads, Y is exactly 400 heads, and Z is exactly either 200 or 400 heads. :smile:

(because X and Y are distinct … ie, they don't overlap … and Z is their union)
 
I was reading documentation about the soundness and completeness of logic formal systems. Consider the following $$\vdash_S \phi$$ where ##S## is the proof-system making part the formal system and ##\phi## is a wff (well formed formula) of the formal language. Note the blank on left of the turnstile symbol ##\vdash_S##, as far as I can tell it actually represents the empty set. So what does it mean ? I guess it actually means ##\phi## is a theorem of the formal system, i.e. there is a...

Similar threads

Back
Top