- #1
CR19
- 4
- 0
Ok, I've had a shot at this problem we've been given in MATLAB. Though I'm very new to physics forums.
I've attached the actual problem and also a few of my equilibrium equations.
I've written out the matrice in MATLAB but I'm guessing its incorrect as the answer I'm getting in Matlab is...
A =
Columns 1 through 12
1.0000 0 0 0.7807 1.0000 0 0 0 0 0 0 0
0 1.0000 0 0.6249 0 0 0 0 0 0 0 0
0 0 0 0 -1.0000 0 0 0 1.0000 0 0 0
0 0 0 0 0 -1.0000 0 0 0 0 0 0
0 0 0 0 0 0 0 -0.7807 -1.0000 0 0 0.7807
0 0 0 0 0 0 0 -0.6249 0 -1.0000 0 -0.6249
0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0
0 0 1.0000 0 0 0 0 0 0 0 0 0
0 0 0 -0.7807 0 0 1.0000 0.7807 0 0 0 0
0 0 0 -0.6249 0 1.0000 0 0.6249 0 0 0 0
0 0 0 0 0 0 -1.0000 0 0 0 1.0000 0
0 0 0 0 0 0 0 0 0 -1.0000 0 0
0 0 0 0 0 0 0 0 0 0 -1.0000 -0.7807
0 0 0 1.0000 0 0 0 0 0 0 0 0
Columns 13 through 16
0 0 0 0
0 0 0 0
0 0 0 0
0 0 0 0
1.0000 0 0 0
0 0 0 0
-1.0000 0 1.0000 0
0 -1.0000 0 0
0 0 -1.0000 -0.7807
0 0 0 -0.6249
0 0 0 0
0 0 0 0
0 0 0 0
0 0 0 0
0 0 0 0.7807
-0.6249 0 0 0.6249
b =
20
0
0
-10
0
-20
0
-10
0
20
0
0
0
0
0
0
x =
20.0000
-394.7389
-334.7389
631.6860
-493.1616
10.0000
12.4934
615.6834
-493.1616
0
12.4934
-583.6781
443.1882
10.0000
443.1882
-567.6755
Results:
x(Ha)=20 [kN]
x(Va)=-394.7389 [kN]
x(1)=-334.7389 [kN]
x(2)=631.686 [kN]
x(3)=-493.1616 [kN]
x(4)=10 [kN]
x(5)=12.4934 [kN]
x(6)=615.6834 [kN]
x(7)=-493.1616 [kN]
x(8)=0 [kN]
x(9)=12.4934 [kN]
x(Ve)=-583.6781 [kN]
x(10)=443.1882 [kN]
x(11)=10 [kN]
x(12)=443.1882 [kN]
x(13)=-567.6755 [kN]
I've written all the equilibrium equation from Horizontal forces Equation 1, Vertical Forces @A Equation 2...but the calculations which I performed by myself I got respectable answers.. But with MATLAB it doesn't appear to give me appropriate answers...
Can anyone help or point me in the right direction.
Many Thanks
I've attached the actual problem and also a few of my equilibrium equations.
I've written out the matrice in MATLAB but I'm guessing its incorrect as the answer I'm getting in Matlab is...
A =
Columns 1 through 12
1.0000 0 0 0.7807 1.0000 0 0 0 0 0 0 0
0 1.0000 0 0.6249 0 0 0 0 0 0 0 0
0 0 0 0 -1.0000 0 0 0 1.0000 0 0 0
0 0 0 0 0 -1.0000 0 0 0 0 0 0
0 0 0 0 0 0 0 -0.7807 -1.0000 0 0 0.7807
0 0 0 0 0 0 0 -0.6249 0 -1.0000 0 -0.6249
0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0
0 0 1.0000 0 0 0 0 0 0 0 0 0
0 0 0 -0.7807 0 0 1.0000 0.7807 0 0 0 0
0 0 0 -0.6249 0 1.0000 0 0.6249 0 0 0 0
0 0 0 0 0 0 -1.0000 0 0 0 1.0000 0
0 0 0 0 0 0 0 0 0 -1.0000 0 0
0 0 0 0 0 0 0 0 0 0 -1.0000 -0.7807
0 0 0 1.0000 0 0 0 0 0 0 0 0
Columns 13 through 16
0 0 0 0
0 0 0 0
0 0 0 0
0 0 0 0
1.0000 0 0 0
0 0 0 0
-1.0000 0 1.0000 0
0 -1.0000 0 0
0 0 -1.0000 -0.7807
0 0 0 -0.6249
0 0 0 0
0 0 0 0
0 0 0 0
0 0 0 0
0 0 0 0.7807
-0.6249 0 0 0.6249
b =
20
0
0
-10
0
-20
0
-10
0
20
0
0
0
0
0
0
x =
20.0000
-394.7389
-334.7389
631.6860
-493.1616
10.0000
12.4934
615.6834
-493.1616
0
12.4934
-583.6781
443.1882
10.0000
443.1882
-567.6755
Results:
x(Ha)=20 [kN]
x(Va)=-394.7389 [kN]
x(1)=-334.7389 [kN]
x(2)=631.686 [kN]
x(3)=-493.1616 [kN]
x(4)=10 [kN]
x(5)=12.4934 [kN]
x(6)=615.6834 [kN]
x(7)=-493.1616 [kN]
x(8)=0 [kN]
x(9)=12.4934 [kN]
x(Ve)=-583.6781 [kN]
x(10)=443.1882 [kN]
x(11)=10 [kN]
x(12)=443.1882 [kN]
x(13)=-567.6755 [kN]
I've written all the equilibrium equation from Horizontal forces Equation 1, Vertical Forces @A Equation 2...but the calculations which I performed by myself I got respectable answers.. But with MATLAB it doesn't appear to give me appropriate answers...
Can anyone help or point me in the right direction.
Many Thanks