Trying to see how these are equivalent

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SUMMARY

The forum discussion centers on the derivation of the angular momentum squared operator in quantum mechanics, specifically the equivalence between two mathematical expressions involving derivatives. The expressions in question are (cotθ)(∂/∂θ) + (∂/∂θ)² and (cscθ)(∂/∂θ)[(sinθ)(∂/∂θ)]. The solution involves applying the product rule to the right side, which simplifies to the left side, confirming the equivalence. This method effectively resolves the confusion regarding the derivation step.

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hideelo
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I am working on the derivation of the angular momentum squared operator (in quantum mech.) and there is one step that I don't see how it works. I'm not sure that this is the right place to post it, but since this is a strictly mathematical question, I figured I would post it here. The equivalence is as follows:

(cotθ)(∂/∂θ) + (∂/∂θ)2 = (cscθ)(∂/∂θ)[(sinθ)(∂/∂θ)]

I don't see how to go from one to the other
 
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hideelo said:
I am working on the derivation of the angular momentum squared operator (in quantum mech.) and there is one step that I don't see how it works. I'm not sure that this is the right place to post it, but since this is a strictly mathematical question, I figured I would post it here. The equivalence is as follows:

(cotθ)(∂/∂θ) + (∂/∂θ)2 = (cscθ)(∂/∂θ)[(sinθ)(∂/∂θ)]

I don't see how to go from one to the other

Start on the right side, and take the derivative of (sinθ * (∂/∂θ)), using the product rule. This simplifies to what you have on the left side without too much effort.
 
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Thanks :-) I don't know why I didnt try that
 

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