Two blocks of mass connect to a pulley

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SUMMARY

The discussion centers on the dynamics of two blocks connected by a massless string over a frictionless pulley. The equations derived include the acceleration of block one (a1 = m2g/(m1+m2)) and the tension in the string (T = (m1*m2*g) / (m1 + m2)). The participants clarified that the tensions in the string are different for each block, leading to the net torque equation τnet = r*T1 - r*T2. The rolling constraint a = rα was also highlighted as essential for solving the problem.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with free body diagrams
  • Knowledge of torque and rotational dynamics
  • Basic principles of frictionless systems
NEXT STEPS
  • Study the concept of net torque in rotational dynamics
  • Learn about the rolling constraint and its applications
  • Explore advanced pulley systems and their dynamics
  • Investigate the effects of friction in pulley systems
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Physics students, educators, and anyone studying mechanics, particularly those focusing on dynamics and rotational motion in systems involving pulleys.

kitsunebell74
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Homework Statement



Blocks of mass and are connected by a massless string that passes over the pulley in the figure . The pulley turns on frictionless bearings, and mass slides on a horizontal, frictionless surface. Mass is released while the blocks are at rest.



Homework Equations



I found a1 for the mass of block one (m1).
a1 = m2g/(m1+m2)
T = (m1*m2*g) / (m1 + m2)
and tension in the string (which is the same everywhere)

The Attempt at a Solution



Now I must find a1 with a mass of the pulley (mp) and radius R.

So far I have drawn my free body diagrams for block 1, block 2, and the pulley. I was able to sum up my forces but I am having trouble summing up the net torque. Will the tensions from the two block be separated? Like this Tnet = r*T1 + r*T2
 
Last edited:
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welcome to pf!

hi kitsunebell74! welcome to pf! :smile:
kitsunebell74 said:
So far I have drawn my free body diagrams for block 1, block 2, and the pulley. I was able to sum up my forces but I am having trouble summing up the net torque. Will the tensions from the two block be separated? Like this Tnet = r*T1 + r*T2

yes, the tensions will be different, and τnet = r*T1 - r*T2

now apply the rolling constraint a = rα :wink:
 
Thanks for the greeting. I figured it out. :)
 

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