Two dimensional Poisson's equation, Green's function technique

omyojj
Messages
32
Reaction score
0
Hi,
While considering perturbed gravitational potential of incompressible fluid in rectangular configuration, I encountered two dimensional Poisson's equation including the step function.
I want to solve this equation

\left( \frac{\partial^2}{\partial x^2} + \frac{\partial^2}{\partial z^2} \right) \psi(x, z) = [ \theta( z - ( a + \epsilon \cos(kx) ) } ) - \theta( z - a ) ] + [ \theta( z - ( - a - \epsilon \cos(kx) ) ) - \theta( z - (- a) ) ]

a is the height from z=0 plane and \epsilon is a small number much smaller than a.
The source term is periodic in x direction with wavenumber k and has a reflection symmetry.
Hence I expect \psi would be also periodic in x-direction and be an even function about z=0 plane.

Do I have to use green's technique here to solve Poisson's equation involving periodic load?
Can it be reduced to Helmholtz equation in one dimension like \psi^{\prime \prime} - k^2 \psi = ... ?

Any help would be greatly appreciated.

Thank you~
 
Last edited:
Physics news on Phys.org
Ok..
What if I simplify the problem?

\left( \frac{\partial^2}{\partial x^2} + \frac{\partial^2}{\partial z^2} \right) \psi(x, z) = \theta(z - ( a + \epsilon \cos(kx) ) }

If I can solve the above one then the superposed solution can be obtained.

help me. T.T
 
Thread 'Direction Fields and Isoclines'
I sketched the isoclines for $$ m=-1,0,1,2 $$. Since both $$ \frac{dy}{dx} $$ and $$ D_{y} \frac{dy}{dx} $$ are continuous on the square region R defined by $$ -4\leq x \leq 4, -4 \leq y \leq 4 $$ the existence and uniqueness theorem guarantees that if we pick a point in the interior that lies on an isocline there will be a unique differentiable function (solution) passing through that point. I understand that a solution exists but I unsure how to actually sketch it. For example, consider a...

Similar threads

Back
Top