Two forces at 45 pull an object distance of 14. What is work by both forces?

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The discussion revolves around calculating the work done by two forces acting at an angle of 45 degrees while moving an object a distance of 14 meters. Each force has a magnitude of 7 N.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss separating the forces into components to determine the effective force in the direction of motion. There is also an attempt to calculate the resultant force using the Pythagorean theorem.

Discussion Status

Some participants are exploring the calculations related to the work done, with one participant expressing confusion over their result and questioning their approach. There is an ongoing examination of the assumptions regarding the distance moved and the components of the forces.

Contextual Notes

Participants are working under the constraints of the problem as presented, with specific values for force and distance, and are questioning the setup and calculations involved in determining work.

evan b
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What is the work done by the two forces together in moving an object a distance of d = 14 m as shown in the diagram? The magnitude of each force is 7 N.
 

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evan b said:
What is the work done by the two forces together in moving an object a distance of d = 14 m as shown in the diagram? The magnitude of each force is 7 N.

Separate the forces into components. What you are interested in are the force components in the direction that the block is actually moved.

W = f * d.
 
ya, so i found force by sqrt of 7^2 + 7^2. then i multiplied it by 7 and go 69.30 J. What am i doing wrong?
 
evan b said:
ya, so i found force by sqrt of 7^2 + 7^2. then i multiplied it by 7 and go 69.30 J. What am i doing wrong?

Isn't the distance it's moved 14?
(The sqrt of 98 looks ok for the force in the direction of motion.)
 

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