- #1

AHinkle

- 18

- 0

## Homework Statement

## Homework Equations

m1

[tex]\Sigma[/tex]F

_{y}=N-m

_{1}g = 0

[tex]\Sigma[/tex]F

_{x}=T=m

_{1}a

(Because there's no friction i see no opposing force to T)

m2

[tex]\Sigma[/tex]F

_{y}=m

_{2}g-T=m

_{2}a

[tex]\Sigma[/tex]F

_{x}=0

## The Attempt at a Solution

m

_{2}g-T=m

_{2}a

T=m

_{1}a

(m

_{1}+m

_{2})a=m

_{2}g-T+T

I notice that the T's cancel when i add the equations together

so it becomes

(m

_{1}+m

_{2})a=m

_{2}g

so...

a=(m

_{2}g)/(m

_{1}+m

_{2})

so...

T=m

_{1}a

T=(m

_{1}) (m

_{2}g)/(m

_{1}+m

_{2})

m

_{1}=6.03kg

m

_{2}=4.68kg

T=(6.03Kg)((4.68Kg)(9.8)/(6.03Kg+4.68Kg))

so...

T=25.8225N

T=m

_{1}a

25.8225N = (6.03Kg)a

a=4.2823 m/s

^{2}

did i do this right?