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Homework Help: Two masses connected by a pulley with a frictionless table

  1. Sep 24, 2010 #1
    1. The problem statement, all variables and given/known data
    physics.jpg


    2. Relevant equations
    m1
    [tex]\Sigma[/tex]Fy=N-m1g = 0
    [tex]\Sigma[/tex]Fx=T=m1a
    (Because theres no friction i see no opposing force to T)

    m2
    [tex]\Sigma[/tex]Fy=m2g-T=m2a
    [tex]\Sigma[/tex]Fx=0


    3. The attempt at a solution

    m2g-T=m2a
    T=m1a

    (m1+m2)a=m2g-T+T
    I notice that the T's cancel when i add the equations together
    so it becomes

    (m1+m2)a=m2g
    so...
    a=(m2g)/(m1+m2)

    so...
    T=m1a
    T=(m1) (m2g)/(m1+m2)

    m1=6.03kg
    m2=4.68kg

    T=(6.03Kg)((4.68Kg)(9.8)/(6.03Kg+4.68Kg))
    so...
    T=25.8225N

    T=m1a
    25.8225N = (6.03Kg)a

    a=4.2823 m/s2
    did i do this right?
    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
  3. Sep 24, 2010 #2

    collinsmark

    User Avatar
    Homework Helper
    Gold Member

    You know, you could have just plugged the numbers in here and saved yourself some work. :smile:
    'Looks right to me. :approve:
     
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