Two methods -- neither works, thevenin

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potatowhisperer
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Homework Statement


we are asked to find the tension between the R6 = 20 ohms resistor, using thevenin[/B]
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Homework Equations


the given solution for Ethev is 27.78

The Attempt at a Solution


is seen in the pictures below

thank i really appreciate your help as it gets frustrating not to know what is wrong .
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i tried a different approach and got this but still wrong
thank you again.
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Hi potatowhisperer, Welcome to Physics Forums.

One of the nice things about Thevenenin's and Norton's theorems is that you can apply them step-wise. You can "break" a circuit at successive locations, incorporating components into an evolving Thevenin or Norton model as you go. Often this can be easier than performing a mesh or nodal analysis of the entire circuit. Consider the suggested circuit "breaks" here:

Fig1.gif


At break (A) you have a simple voltage divider to the left. So a Thevenin equivalent is trivial to find. At (B) an "open" resistance R3 is tacked on, modifying the Thevenin resistance. Simple! Then at (C) the then-current Thevenin model is part of a voltage divider with R5, so again a trivial reduction...

Give it a try!
 
Bon jour, potatowhisperer,

Your first solution, the nodal analysis, is ok until the very end. You did something wrong when you used your matrix solver.

?temp_hash=852ab311d37be5847cf92a2503f323ba.png


You must have made some such error.
 

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I love y'all
i m glad that the first method was just a calculation mistake , though i am embarrassed to have taken your time just because of a sign, i really appreciate your help again.
about the second method , i can not thank you enough for telling that it was unfinished calculations , as i was confused cause now i can think more logically about what i m doing , i have had many instances when i got so frustrated with my mistakes that i would just stop ... so thank you very much.
 
GNEILL,I am definitely going to try that method, it does simplify things , A LOT .