Two objects, one accelerating downwards onto another

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An object accelerating downwards exerts less force on the surface below compared to when it is stationary, due to Newton's third law. The lower object experiences a reduced retarding force from the descending object, which affects the overall dynamics. If the retarding force were to increase, the downward acceleration of the falling object would decrease, potentially leading to a complete stop if sustained long enough. The discussion highlights the complexity of force interactions in accelerating systems. Clarification on the specifics of force calculations in these scenarios is sought.
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The object accelerating downward exerts less force on the part below than if it were being held in place, But this is a reflexive situation: the lower section exerts less retarding force on the descending object - Newton's 3rd law. If the retarding force were greater, the object would have less downward acceleration and, if the force were great enough for long enough time, there could be arrest.

I wanted to know if I had this right? I think it is correct from what I have tried to research.

Any input would be appreciated, thanks
 
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BUMP please...anyone?
 
There isn't enough information to answer your question. What the force would be depends upon how fast the dropped object takes to stop.
 
Illuminist14 said:
The object accelerating downward exerts less force on the part below than if it were being held in place, But this is a reflexive situation: the lower section exerts less retarding force on the descending object - Newton's 3rd law. If the retarding force were greater, the object would have less downward acceleration and, if the force were great enough for long enough time, there could be arrest.

I wanted to know if I had this right? I think it is correct from what I have tried to research.

Any input would be appreciated, thanks

Your previous thread about this was locked. Do not re-post a locked thread.

https://www.physicsforums.com/showthread.php?t=569058

.
 
For simple comparison, I think the same thought process can be followed as a block slides down a hill, - for block down hill, simple starting PE of mgh to final max KE 0.5mv^2 - comparing PE1 to max KE2 would result in finding the work friction did through the process. efficiency is just 100*KE2/PE1. If a mousetrap car travels along a flat surface, a starting PE of 0.5 k th^2 can be measured and maximum velocity of the car can also be measured. If energy efficiency is defined by...

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