Stopping acceleration and starting to move at constant speed

In summary, acceleration is the rate of change of an object's velocity over time and is a vector quantity with both magnitude and direction. It is important to stop acceleration and start moving at a constant speed for predictability, control, and safety. The factors that affect an object's acceleration include net force, mass, and initial velocity. To stop acceleration and start moving at a constant speed, an opposite force must be applied. Acceleration and deceleration are both terms describing changes in an object's velocity, with acceleration referring to an increase in velocity and deceleration referring to a decrease.
  • #1
Zaephou
4
1
I have an example:

Let us say you are on a large object with a mass of 5x10^10kg accelerating upwards at a constant velocity of 5m/s^-2, and there is a ball 0.1kg on top of that object. This ball should be accelerating at the same pace.

The ball is then held up 5m from the surface of that object, and is let go. Would the ball stop accelerating and start moving at a constant velocity considering the downward forces are negligible.

Further questions:

-What force would this ball have when it is let go?

-Would the large object ever reach the ball again?

-If the ball does start moving at a constant velocity, when the large object reaches the ball, how large of a force will that object exert on the ball, and would this cause the ball to accelerate at what pace?
 
  • Like
Likes bsheikho
Physics news on Phys.org
  • #2
The situation can be understood in terms of Einstein's Equivalence Principle. The behavior of the ball, as observed by someone on the large mass, will be exactly the same as that of a ball on a planet that, at its surface, has a gravitational acceleration half that of what applies at the surface of the Earth - ie 'one half G'.

So when released, the ball will 'fall' towards the big mass (meaning it stops accelerating and the mass accelerates towards it). It will hit the mass after ##\sqrt2## seconds, at which point it will either stick to the mass or bounce, depending on the construction of the ball.
 
  • Like
Likes NihalRi
  • #3
Zaephou said:
Would the ball stop accelerating
F=ma. No horizontal force = no horizontal acceleration.
 
  • #4
Zaephou said:
I have an example:

Let us say you are on a large object with a mass of 5x10^10kg accelerating upwards at a constant velocity of 5m/s^-2, and there is a ball 0.1kg on top of that object. This ball should be accelerating at the same pace.

The ball is then held up 5m from the surface of that object, and is let go. Would the ball stop accelerating and start moving at a constant velocity considering the downward forces are negligible.

Further questions:

-What force would this ball have when it is let go?

-Would the large object ever reach the ball again?

-If the ball does start moving at a constant velocity, when the large object reaches the ball, how large of a force will that object exert on the ball, and would this cause the ball to accelerate at what pace?
I agree. The ball would be at constant velocity and therefore there is no force acting on it. Since the object was accelerating to begin with, it would reach the ball and it would appear as if the ball was falling towards the object.
 
  • #5
andrewkirk said:
The situation can be understood in terms of Einstein's Equivalence Principle. The behavior of the ball, as observed by someone on the large mass, will be exactly the same as that of a ball on a planet that, at its surface, has a gravitational acceleration half that of what applies at the surface of the Earth - ie 'one half G'.

So when released, the ball will 'fall' towards the big mass (meaning it stops accelerating and the mass accelerates towards it). It will hit the mass after ##\sqrt2## seconds, at which point it will either stick to the mass or bounce, depending on the construction of the ball.

Considering this, how much force would the object exert on the ball upon contact? (If the force is large, why does it only cause the ball to bounce on the surface?)
 
  • #6
Zaephou said:
Considering this, how much force would the object exert on the ball upon contact?
The force will vary over the period for which the ball is in contact with the mass. It will start at zero, increase to a maximum, then decline back to zero. The final zero is reached when the ball loses contact (if it bounces) or when it is fully stationary with respect to the mass (if no bounce). The pattern of force over time, and the maximum force experienced, depend on the construction of the ball and of the mass's surface. The calculation would be complex and need a great deal of extra information about the ball and surface.
 

What is acceleration?

Acceleration is the rate of change of an object's velocity over time. It is a vector quantity, meaning it has both magnitude (speed) and direction.

Why is it important to stop acceleration and start moving at constant speed?

Stopping acceleration and starting to move at constant speed is important because it allows for a more predictable and controlled motion. It also reduces the risk of potential accidents and allows for smoother and more energy-efficient movement.

What factors affect an object's acceleration?

The factors that affect an object's acceleration include the net force acting on the object, the object's mass, and the object's initial velocity. The direction of the net force also affects the direction of the acceleration.

How can we stop acceleration and start moving at constant speed?

To stop acceleration and start moving at constant speed, we need to apply a force in the opposite direction of the acceleration. This will gradually decrease the acceleration until it reaches zero, resulting in constant speed.

What is the difference between acceleration and deceleration?

Acceleration and deceleration are both terms used to describe changes in an object's velocity. However, acceleration refers to an increase in velocity (speeding up), while deceleration refers to a decrease in velocity (slowing down).

Similar threads

Replies
24
Views
1K
Replies
11
Views
2K
Replies
11
Views
1K
Replies
22
Views
21K
Replies
1
Views
792
Replies
2
Views
708
  • Mechanics
Replies
10
Views
1K
Replies
6
Views
905
Back
Top