Two rods with fixed angle, find the velocity of the crossing point

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The discussion centers on the velocity analysis of two rods with a fixed angle, specifically addressing the confusion around vector decomposition in parts (a) and (b) of the problem. In part (a), the velocity of point A is defined as v_A = -v_1 j hat, while in part (b), it is expressed as v_A = v2 sin(theta) i hat + (-v1 - v2 cos(theta)) j hat. The key takeaway is that point A must move along the directions of both rods, l1 and l2, simultaneously, which necessitates the inclusion of additional components in the velocity vector.

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Homework Statement
Two straight rods l1 and l2 are put on a piece of paper as shown in the figure. the angle between two rods is theta. What is the velocity of the crossing point A when l1 starts to roll with velocity v1? What about if l2 also starts to roll with velocity v2?
Relevant Equations
Vector decomposition
I apologize if this is a stupid question but how come we can't just say that for part (a) v_A = -v_1 j hat, and for (b) v_A=v2 sintheta i hat + (-v1-v2cos theta) j hat? i.e. how come we can't just do vector decomposition "normally"? I am especially confused about the given solution in (a) where there is an additional horizontal component of velocity in the i directioneven though v1 appears to only act in the j direction.

Thanks

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For a), A must move along the direction of l2.
For b), A must move along the direction of l2 and l1 simultaneously.
 
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