Two Variable Equation Word Problem

homegrown898
Messages
16
Reaction score
0
A club consisting of seniors and juniors has 15 members. After seven more seniors and three more juniors join the club, the ratio of juniors to seniors is 2:3. How many juniors are in the club?

I guess the thing that screws me up is the ratio part. I don't know what to do. I've found a negative number for J but that can't be right. Right now, I think there are 10 juniors in the club but I really don't know how to prove that. I kind of came upon that number accidentally.
 
Mathematics news on Phys.org
There are 25 members, 2/5 are junior and 3/5 are senior. Got it?
 
10 sounds right

put the problem in mathematical terms:
juniors = j , seniors = s
j+s=15.....(1)
3 more juniors and 7 more seniors join.. so we'll have j+3 juniors and s+7 seniors
now the ratio of new j to new s is 2:3
that means :
j+3/s+7 = 2/3......(2)

so now u have 2 equations (1) and (2) with 2 unknowns that u can solve to find out what j equals to
 
The main difficulty with the original problem information is that there is unneccesary information. All you need is a total of 25 members and the 2:3 ratio of juniors to seniors. The fact that there were originally 15 members and seven added seniors and seven added juniors is extraneous. The only point would be if the question was how many of the original 15 were juniors or seniors.
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
Fermat's Last Theorem has long been one of the most famous mathematical problems, and is now one of the most famous theorems. It simply states that the equation $$ a^n+b^n=c^n $$ has no solutions with positive integers if ##n>2.## It was named after Pierre de Fermat (1607-1665). The problem itself stems from the book Arithmetica by Diophantus of Alexandria. It gained popularity because Fermat noted in his copy "Cubum autem in duos cubos, aut quadratoquadratum in duos quadratoquadratos, et...
Thread 'Imaginary pythagorus'
I posted this in the Lame Math thread, but it's got me thinking. Is there any validity to this? Or is it really just a mathematical trick? Naively, I see that i2 + plus 12 does equal zero2. But does this have a meaning? I know one can treat the imaginary number line as just another axis like the reals, but does that mean this does represent a triangle in the complex plane with a hypotenuse of length zero? Ibix offered a rendering of the diagram using what I assume is matrix* notation...

Similar threads

Replies
30
Views
4K
Replies
7
Views
3K
Replies
3
Views
2K
Replies
8
Views
2K
Replies
1
Views
3K
Replies
28
Views
7K
Back
Top