U-Substitution for ∫3xdx/√(1-2x)

zachem62
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Homework Statement



∫3xdx/√(1-2x)

Homework Equations





The Attempt at a Solution



so i tried making u=3x which makes du=3dx but that substitution doesn't get rid of the x unde the square root. i tried u=1-2x and that gives du=-2dx and that doesn't get rid of the x on top. So I'm stuck and have no idea what to do here. Please help me out. Thanks!
 
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zachem62 said:

Homework Statement



∫3xdx/√(1-2x)

Homework Equations





The Attempt at a Solution



so i tried making u=3x which makes du=3dx but that substitution doesn't get rid of the x unde the square root. i tried u=1-2x and that gives du=-2dx and that doesn't get rid of the x on top. So I'm stuck and have no idea what to do here. Please help me out. Thanks!
Your second substitution will work if you replace x and dx with the corresponding values of u and du. Note that if u = 1 - 2x, then x = (1/2)(1 - u).
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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