U-Substitution for Indefinite Integrals

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Homework Help Overview

The discussion revolves around the application of U-substitution in evaluating an indefinite integral involving a polynomial expression.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to apply U-substitution to the integral of x^2(x^3 + 5)^9 dx, initially defining u and calculating du. Some participants question the correctness of the differentiation step in finding du, suggesting a need for careful checking of the derivative.

Discussion Status

Participants have provided feedback on the original poster's approach, noting a mistake in the differentiation of u. The discussion reflects a collaborative effort to clarify the correct application of U-substitution, with some guidance offered on maintaining proper notation.

Contextual Notes

There is an emphasis on ensuring that all components of the integral, including dx, are correctly included in the substitution process. The original poster has acknowledged the feedback and is attempting to correct their approach.

01010011
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Hi, am I on the right track with this U-substitution problem?

Homework Statement



Evaluate the indefinite integral

Homework Equations



integral of x^2(x^3 + 5)^9 dx

The Attempt at a Solution



integral of x^2(x^3 + 5)^9 dx

Let u = x^3 + 5

du = 2x^2

1/2du = x^2

1/2 integral u^9 du

1/2 (u^10)/10 + c

1/20 u^10 + c

1/20 (x^3 + 5)^10 + c
 
Last edited:
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You are on the right track, but I would check that du again.
 
01010011 said:
Let u = x^3 + 5

du = 2x^2

This is where you're wrong. Just a slight mistake,

Remember that the differentiation of x^n is n*x(n-1)
 
Dick said:
You are on the right track, but I would check that du again.

Lunat1c said:
This is where you're wrong. Just a slight mistake,

Remember that the differentiation of x^n is n*x(n-1)

Thanks for your replies Dick and Lunat1c. I see the mistake, i'll try it again:


The Attempt at a Solution



integral of x^2(x^3 + 5)^9 dx

Let u = x^3 + 5

du = 3x^2 dx

1/3du = x^2 dx

1/3 integral u^9 du

1/3 (u^10)/10 + c

1/30 (u^10) + c

1/30 (x^3 + 5)^10 + c
 
You put the dx in this time. That's a good habit to get into, especially when you start doing trig substitutions.
 
Thanks Mark44
 

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