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UBER EASY QUESITON: just need to make sure

  1. May 20, 2010 #1
    Just a general question. If you drop a object (air resistance negligible) and you know the t initial is 0 and you know the t final is w/e you get on your stop watch. You do d/t to get average velocity of the fallen object.

    Now that you have the avrg velocity you know the V initial is zero and the speed rises to the avrg velocity, can you assume that a = Vavrg/t?

    Im in IB physics HL but just cant get my head around this one for some reason....
  2. jcsd
  3. May 20, 2010 #2
    Why do you think the speed only rises to the average velocity? If you assume constant acceleration and you had a way to measure the final velocity, then you would be right. But the average velocity would be reached at 1/2 t_final and keep increasing after that...

    Out of the data you have (t and d) you can find out a by using [tex]d = \frac{1}{2} a t^2[/tex]
  4. May 20, 2010 #3
    haha wow I feel like an idiot. Thanks.
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