Uncovering the Mystery of Particle Vibrations

AI Thread Summary
Particles of substances vibrate due to thermal energy, which is essentially heat. This vibration can be modeled by treating atoms and their bonds as masses connected by springs, with the vibrational modes referred to as phonons. Even in a vacuum, where there is no external heat source or electromagnetic radiation, particles will still vibrate due to zero-point energy, a concept from quantum mechanics. At absolute zero (0 Kelvin), molecular vibration persists because of this inherent energy, which prevents atoms from becoming unlocalized. The Heisenberg Uncertainty Principle supports this by indicating that if momentum were to be zero, position uncertainty would become infinite. The energy of a simple harmonic oscillator at zero-point energy is quantified, illustrating the fundamental nature of these vibrations.
Bubonic Plague
Messages
94
Reaction score
0
Why do the particles of substances vibrate? Just where does that constant energy come from?
 
Physics news on Phys.org
It comes from thermal energy (aka heat), dude. We can approximate the atoms of a material and their bonds as an array of masses with each mass being coupled to its nearest neighbors by springs. The modes of vibration are known as phonons.

eNtRopY
 
It comes from thermal energy (aka heat), dude. We can approximate the atoms of a material and their bonds as an array of masses with each mass being coupled to its nearest neighbors by springs. The modes of vibration are known as phonons.

Good. Let's say i were to put the substance in vacuum, will it's particles still vibrate, now that it has no source of heat? Let's also say that it is shielded from electromagnetic radiation.
 
Originally posted by Bubonic Plague
Good. Let's say i were to put the substance in vacuum, will it's particles still vibrate, now that it has no source of heat? Let's also say that it is shielded from electromagnetic radiation.

Yes.

Let's go a step further and say that you have put a substance in a vacuum and achieved a material temperature of zero kelvin. There would still be molecular vibration. This phonon mode is known as the the zero-point energy. It's a quantum mechanical thing, but conceptually it makes sense. There is a minimum amount of kinetic energy that must be present; otherwise, the atoms in the lattice will be highly unlocalized...

Remember the Heisenberg Uncertainty Principle:

delta x delta p ~ h.

So, having delta p at zero would cause delta x to tend towards infinite.

Anyway in case your interested, the zero-point energy of a simple harmonic oscillator is given as:

E0 = (1/2) hbar omega.

The energies of all higher modes are:

En = (n + 1/2) hbar omega.

eNtRopY
 
Last edited by a moderator:
Toponium is a hadron which is the bound state of a valance top quark and a valance antitop quark. Oversimplified presentations often state that top quarks don't form hadrons, because they decay to bottom quarks extremely rapidly after they are created, leaving no time to form a hadron. And, the vast majority of the time, this is true. But, the lifetime of a top quark is only an average lifetime. Sometimes it decays faster and sometimes it decays slower. In the highly improbable case that...
I'm following this paper by Kitaev on SL(2,R) representations and I'm having a problem in the normalization of the continuous eigenfunctions (eqs. (67)-(70)), which satisfy \langle f_s | f_{s'} \rangle = \int_{0}^{1} \frac{2}{(1-u)^2} f_s(u)^* f_{s'}(u) \, du. \tag{67} The singular contribution of the integral arises at the endpoint u=1 of the integral, and in the limit u \to 1, the function f_s(u) takes on the form f_s(u) \approx a_s (1-u)^{1/2 + i s} + a_s^* (1-u)^{1/2 - i s}. \tag{70}...
Back
Top