Underdamped harmonic oscillator with a sinusoidal driving force

Click For Summary
The discussion focuses on finding the driving frequency ωd that maximizes both displacement and velocity amplitudes in an underdamped harmonic oscillator subjected to a sinusoidal driving force. Participants emphasize the importance of using differential calculus to determine these maxima, with hints provided on relevant equations and concepts. There is confusion regarding the provided equation for displacement, particularly the absence of time and the meaning of the variable gamma. Suggestions include using the relationship between force, potential energy, and acceleration to derive the necessary equations. The conversation highlights the need for clarity in the mathematical formulation to effectively solve the problem.
captainemeric
Messages
8
Reaction score
0

Homework Statement


Consider an underdamped harmonic oscillator (Q > 1/2) with a sinusoidal driving
force Focos(ωdt).
(a) (5 pts) By using differential calculus find ωd that maximizes the displacement amplitude.
(b) (7 pts) By using differential calculus find ωd that maximizes the velocity amplitude.


Homework Equations


x(t)= (fo/m)/sqrt([wo^2-wd^2]^2+(gama(wd)^2)



The Attempt at a Solution


I know what the end solution will be and the general theory behind this but I am unsure how to proceed. I am unsure how to prove the point at which it is the maximum.
 
Physics news on Phys.org
The clue is pretty much in "differential calculus". What tool have you learned in calculus for finding the maximum of a function?
 
captainemeric said:

Homework Statement


Consider an underdamped harmonic oscillator (Q > 1/2) with a sinusoidal driving
force Focos(ωdt).
(a) (5 pts) By using differential calculus find ωd that maximizes the displacement amplitude.
(b) (7 pts) By using differential calculus find ωd that maximizes the velocity amplitude.


Homework Equations


x(t)= (fo/m)/sqrt([wo^2-wd^2]^2+(gama(wd)^2)



The Attempt at a Solution


I know what the end solution will be and the general theory behind this but I am unsure how to proceed. I am unsure how to prove the point at which it is the maximum.

Let me give you a hint on the general theory behind this:

your relevant equation seems flat bizarre

first of all, why is there no 't' in x(t)

and what is gama?
---------

to set you in the direction i would go:

you have your driving force F

F=-d/dx(V(x)

then V(x) = potential energy

maximum value of V(x)= total energy = 1/2*mass*velocity^2+V(x)

then solve for velocity, and integrate with respect to time to get x(t).
---------
or just say (1/m)*F= acceleration and integrate twice with respect to time to get x(t)

-----
 
Thread 'Correct statement about size of wire to produce larger extension'
The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...

Similar threads

Replies
9
Views
2K
Replies
7
Views
2K
  • · Replies 12 ·
Replies
12
Views
3K
Replies
5
Views
2K
  • · Replies 18 ·
Replies
18
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
17
Views
3K
  • · Replies 12 ·
Replies
12
Views
2K
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K