Understand Decreasing Function: Limit g'(x) at Infinity

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SUMMARY

The discussion centers on understanding the behavior of the derivative g'(x) as x approaches infinity, given that function h is decreasing on the interval [4, ∞) and approaches a limit of 8. It is established that since h approaches a constant value, the derivative h'(x) must approach 0 as x approaches infinity. This indicates that while h is decreasing, its rate of change diminishes, leading to the conclusion that g'(x) will also approach 0 under these conditions.

PREREQUISITES
  • Understanding of limits in calculus
  • Knowledge of derivatives and their properties
  • Familiarity with decreasing functions
  • Concept of neighborhoods in mathematical analysis
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  • Study the concept of limits and continuity in calculus
  • Learn about the behavior of derivatives of decreasing functions
  • Explore the implications of the Mean Value Theorem
  • Investigate the relationship between a function approaching a constant and its derivative
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Sethka
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Now what should I look up to understand a question like this one:

Function h is decreasing on the interval [4,infinity) and lim h(x)(with x approaching infinity)=8, what would be the limit g'(x)(with x approaching infinity)?

I don't nessicarily need the answer, but could someone point me in the right direction?
 
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Earlier you asked about a function g that was simply decreasing and were told that you cannot say anything about the derivative as x went to infinity except that it would be non-negative (the limit could be 0).

Is this a revision of that problem? If so, it is a good revision. (I won't make any remark about not being able to find g' from information about h!) The difference now is that h goes to a constant as x goes to infinity- that's more important than "decreasing". Given any [itex]\epsilon> 0[/itex], there must exist a "neighborhood of infinity" (interval [itex](a, \infty)[/itex]) on which h(x) differs less than [itex]\epsilon[/itex] from 8. What does that tell you about the derivative of h?
 

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