Austin0 said:
with #2 i have question.
With inertial frames the charts are fundamentally Euclidean and the metrics static so you can superpose the traveler chart with linear , one to one correspondense over an extended time range..
An accelerated chart has a dynamic metric and is in a sense inherently non-Euclidean
It can map (assign coordinates ) unambiguously to a flat manifold but I do not see how an extended time range of such a chart can be linearly mapped to a single uniform orthogonal matrix .
Several issues here: changing coordinates does not change geometry. Changing coordinates with changed metric
preserves geometric objects, including the curvature tensor. If a manifold is flat (e.g. SR) it has zero curvature in all coordinates.
Who said linearly? You can draw polar coordinate lines on cartesian coordinates just fine. The transform is non-linear. The Euclidean geometry metric expressed in polar coordinates is no longer diag(1,1), but the curvature tensor is still identically zero everywhere. You don't make a plane curved by drawing different coordinates on it.
I don't mean to be insulting, but have you read any introduction to differential geometry?
My point, intended to be obvious, is that if you have one coordinate chart that covers a complete manifold, and you have any other coordinate chart (which provides one label for every point in the manifold in the manifold that it covers, and is continuous one-one mapping from any other coordinate chart for portions that overlap), then any coordinate chart can be plotted on any chart that covers the whole manifold - as the standard Minkowski coordinates do.
Austin0 said:
With an accelerated frame it seems to me that with a dynamic metric the set of coordinate events logging a particular time value could not possibly fall on a straight line in the rest frame. Yet this is exactly what is portrayed by a straight line of simultaneity attached to such an accelerated frame.
I never said or implied that another coordinate chart's coordinate lines have to be straight when plotted in an inertial chart. It was Bobc2 who wanted to do this. My point is that straight or not, if two lines intersect, a coordinate change won't make them not intersect. If you are proposing simultaneity surfaces (or line restricted to x-t plane) that curve, you are emphatically
not talking about the same simultaneity lines as Bobc2. I have stated a few time that not only is it possible to construct simultaneity lines that agree closely with MCIF near the traveler world line but differ at distances from it such that they never intersect, but that there are uncountably infinite ways of doing this with no clear way to prefer one over the other.
Austin0 said:
It charts an implicit assumption that simply because the traveler momentarily adopts the synchronization of a MCRF that this makes the frame congruent with the history of the MCRF.
I think such lines are actually misleading during accleration in both directions but in the case of towards Earth they don't lead to obvious anomalies because when the traveler does go inertial, the traveler frame then does become congruent with the future of the final MCRF .So the intersection of that line with the Earth does agree with the later appearence of the traveler clock there.
I completely agree with this.
Austin0 said:
Well here I must beg to differ.I think that not only is the region from the intersection through divergence not a geometric fact I think it is totally non-existent. It is purely a mental construct produced by falsely assuming the simultaneity planes from a series of MCRFs has any correspondence to the accelerated traveler frame in this region..
That is exactly what Bobc2 was doing. It is not a 'false' way of doing things, just a way that provides limited coordinate coverage. There is no such thing as 'false' coordinates. As for alternatives that don't have this intersection problem for any twin scenario, two that I know of that have names are
radar simultaneity and
Minguzzi simultaneity. I thought you were claiming that the intersections of MCIF lines could be removed by coordinate transform. That is nonsense. However, it is certainly possible pick different simultaneity lines that don't have intersections (uncountably many ways to do so).
Austin0 said:
I am somewhat surprised by you as you seem to be agreeing with bobc2 on this point. WHile he embraces this interpretation with all its unlikely implications , you want to excise it from the chart for coordinate misbehavior.
I agree with Bobc2 that it is a possible choice for simultaneity; it is a quite useful one
locally. I disagree with Bobc2 that it has any more physical meaning globally than any number of other choices, and that where it has ridiculous implications, that means - mathematically - that it has become an invalid method of mapping spacetime.
Austin0 said:
but both seem to agree that it does represent the accelerated frame with instantaneous conventional synchronization.
No, I claim there is
no preferred synchronization for non-inertial observers. I thought I have explained in great detail that the reason there is one for inertial observers is that any reasonable method of synchronizing separated clocks agrees with any other. For non-inertial observers, essentially every method of synchronizing separated clocks disagrees with all the other methods, so there is no reasonable basis to claim a preference.
Austin0 said:
I suggest that it simply has no relation to the accelerated frame or a traveler chart constructed with this convention. That the events portrayed in that region map events in the past of the various MCRFs but do not map any events of the accelerated frame. They would not appear in the traveler chart nor would they appear in the chart of any inertial frame logging the locations and times of the accelerated frame.
I agree with this.
Austin0 said:
My understanding was that adopting the synchronization of a series of MCRFs automatically defined the math to be the normal L.T. and metric.
No, this is not correct. If you adopt the series of MCIF simultaneity lines, parametrized by proper time along a non-inertial path, you get a chart (covering only part of spacetime) with a metric completely different from diag(1,-1,-1,-1). However, the geometry it describes is the same: curvature is still zero; all invariants come out the same.
Austin0 said:
So the difference is only in my approach in applying that math.
That approach was simplistic. Start with a hypothetical physical system of clocks and rulers and then determine what the chart of such a system would look like with continuous resynchronization conforming to the MCRFs.
How the clock readings would evolve over time at various locations within the frame.
With this simple model certain things seem clear.
I don't know what this part means. A fundamental property of non-inertial world lines in SR is:
- rigid rulers are cannot extend very far, even assuming the artifice of Born rigidity
- the Einstein clock synchronization convention disagrees with rigid ruler simultaneity, even where they both apply.
Given this, I truly have no idea what you are describing.
Austin0 said:
All inertial frames would chart the physical system proceeding uniformly through time.That this log of positions and times is independent of any clock readings or synch convention occurring within the frame. SO any implemented convention could only change the observed clock readings but not effect any change in the position of the frame as indicated by the rotating x' axes attached to the accelerated frame in the standard chart.
So in my description of the events in the instant turnaround scenario with the traveler clocks being turned back along the line towards Earth (overlapping coordinates) and turned forward outward from the traveler (coordinate gap), I was describing a frame independent reality. The physical event of changing a clock time is invariant. Inertial frames would assign their own coordinates to these events but all frames must agree on the numerical values of the change and where they occurred in the traveler frame. Agreed?.
If I understand this, it is complete nonsense. But maybe you have not made your meaning clear.
What each observer sees of the the other clock is continuous forward only movement, always. What they choose to interpret about the relationship between what they see and what is 'now' - which is purely a convention - is up for grabs, but one thing prohibited for a mathematically valid mapping is reversal of causality along a distant world line.