Understanding BJT Emitter Resistance: Explained by Horowitz & Hill

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SUMMARY

The discussion centers on the intrinsic emitter resistance (r'e) in BJT circuits, specifically as described in "The Art of Electronics" by Horowitz & Hill. Participants clarify that r'e represents the dynamic resistance of the base-emitter diode and is often confused with the actual emitter resistor (Re) connected to ground. The output impedance of an emitter follower circuit is determined by the parallel combination of Re and the impedance of the base circuit, adjusted by the transistor's beta factor. A pull-down resistor is recommended to prevent floating output potentials when the load is disconnected.

PREREQUISITES
  • Understanding of BJT operation and characteristics
  • Familiarity with "The Art of Electronics" by Horowitz & Hill
  • Knowledge of AC impedance concepts in electronic circuits
  • Basic circuit analysis techniques, including parallel and series combinations
NEXT STEPS
  • Study the concept of dynamic resistance in BJTs, focusing on r'e calculations
  • Learn about output impedance in emitter follower configurations
  • Research the role of pull-down resistors in preventing floating outputs
  • Explore the impact of transistor beta on circuit performance and impedance
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Electronics students, circuit designers, and engineers seeking to deepen their understanding of BJT emitter configurations and impedance analysis.

garibaldi
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Hey everyone,

Im currently reading Horowitz & Hill and am a little confused on the topic of the intrinsic emitter resistance (re). I understand that this resistance is essentially the dynamic resistance of the base-emitter diode.

I assumed that when analyzing a circuit this resistance should always be placed in series with the emitter. However H&H seem to place this resistance from the emitter to ground in the emitter followers they demonstrate.

In the case of the emitter follower circuit this makes sense because the low re means that the circuit will have a low output resistance as expected. I just don't understand why they placed it to ground.

The circuits in question are attached.
 

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What makes you think that the resistors from emitter to ground shown in the images are re, the intrinsic emitter resistance? They aren't labeled re.
 
I think you mean r'e or pronounced 'R prime E' or 'R E prime'. Summarized, R'e is the AC impedance of the base emitter junction. Normally the output imedance of an emitter follower is Re (actual resistor from emitter to ground) in parallel with [(beta*the base circuit impedance) + r'e].
 
You say:

"Normally the output imedance of an emitter follower is Re (actual resistor from emitter to ground) in parallel with [(beta*the base circuit impedance) + r'e]."

Shouldn't the "(beta*the base circuit impedance)" expression be something more like "(the base circuit impedance/beta)"? Actually, I think the "beta" should be "beta+1".
 
The Electrician said:
You say:

"Normally the output imedance of an emitter follower is Re (actual resistor from emitter to ground) in parallel with [(beta*the base circuit impedance) + r'e]."

Shouldn't the "(beta*the base circuit impedance)" expression be something more like "(the base circuit impedance/beta)"? Actually, I think the "beta" should be "beta+1".

Yes, my bad.
 
It is usually a good idea to have a pull-down resistor on the emitter output to keep the output potential from floating up to the base potential when the external load is not connected. It is absolutely necessary if the external load does not have a dc path to ground.
 

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